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miskamm [114]
1 year ago
8

What is the most useful meteorological measurement for forecasting freezing precipitation?

Physics
1 answer:
scoray [572]1 year ago
6 0

The most useful meteorological measurement for forecasting freezing precipitation is b. radiosonde soundings

<h3>Radiosonde </h3>

At high altitudes, radiosondes are battery-powered telemetry sensor bundles that detect altitude, pressure, temperature, relative humidity, wind (both speed and direction), and cosmic ray measurements. They are commonly taken into the atmosphere by weather balloons.

Rawindsonde is an acronym for radar wind sonde, a type of radiosonde that tracks its position as it rises through the sky to provide wind speed and direction. Another type of radiosonde is one that falls to the ground after being released from an aircraft, as opposed to being carried by weather balloons. The term "dropsondes" is used to describe this group of radiosondes. The majority of operational atmospheric data assimilation methods depend heavily on radiosondes.

Learn more about radiosonde here:

brainly.com/question/10510287

#SPJ4

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The fulcrum is the
olga_2 [115]

Answer:

point of support on which a lever rotates.

Explanation:

The fulcrum is the point of support on which a lever rotates. Fulcrum is a pivotal part of simple machines.

The fulcrum provides the platform for a lever to torque.

  • The force that opposes motion by the applied force is termed the frictional force.
  • Friction is a force that opposes motion.
  • The stored energy of an object is its potential energy.
  • The potential energy is the energy due to the position of a body.
  • The distance an object moves when doing work is termed its displacement.
6 0
2 years ago
How much Nitrogen (N) atoms are in this 3NH4Cl?
mihalych1998 [28]

Answer:

3

Explanation:

7 0
3 years ago
A object weighing 5 kg, starts to accelerate evenly on a horizontal line. A force moves the object
hammer [34]
Work= force*distance
Work= x*12
Force= mass*acceleration
Force= 5 kg*6
Force= 40 N
Work= 40×12
Work= 480 J (joules)
I think this is it
5 0
3 years ago
A 225 kg block is pulled by two horizontal forces. The first force is 178 N at a 41.7-degree angle and the second is 259 N at a
yawa3891 [41]

Answer:

52.9 N, 364.7 N

Explanation:

First of all, we need to resolve both forces along the x- and y- direction. We have:

- Force A (178 N)

A_x = (178 N)(cos 41.7^{\circ})=132.9 N\\A_y = (178 N)(sin 41.7^{\circ})=118.4 N

- Force B (259 N)

B_x = (259 N)(cos 108^{\circ})=-80.0 N\\B_y = (259 N)(sin 108^{\circ})=246.3 N

So the x- and y- component of the total force acting on the block are:

R_x = A_x + B_x = 132.9 N - 80.0 N =52.9 N\\R_y = A_y + B_y = 118.4 N +246.3 N = 364.7 N

7 0
2 years ago
A juggler throws a bowling pin straight up with an initial speed of 8.20 m/s. How much time elapses until the bowling pin return
tensa zangetsu [6.8K]

Answer:

1.68 s

Explanation:

From newton's equation of motion,

a = (v-u)/t.................................. Equation 1

Making t the subject of the equation

t =(v-u)g............................. Equation 2

Where t = time taken for the bowling pin to reach the maximum height, v = final velocity bowling pin, u = initial velocity of the bowling pin, g = acceleration due to gravity.

Note: Taking upward to be negative and down ward to be positive,

Given: v = 0 m/s ( at the maximum height), u = 8.20 m/s, g = -9.8 m/s²

t = (0-8.20)/-9.8

t = -8.20/-9.8

t = 0.84 s.

But,

T = 2t

Where T = time taken for the bowling pin to return to the juggler's hand.

T = 2(0.84)

T = 1.68 s.

T = 1.68 s

7 0
3 years ago
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