Question

What is the composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu?

Answer 1

The composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu is 29.4 at % and 70.6 at % for Zn and Cu respectively.

How to convert weight % to atom %?

The weight percentage of an element can be converted to atom percentage as follows:

1. C(Zn) = C1A2 / (C2A1) + (C1A2) × 100
2. C(Cu) = C2A1 / (C1A2) + (C2A1) × 100

Where;

• C1 = 30
• C2 = 70
• A1 = 65.4g/mol
• A2 = 63.55g/mol

• C(Zn) = {30*63.55} / (70*65.4) + (30*63.55) × 100
• C(Cu) = {70*65.4} / (30*63.55) + (70*65.4) × 100

• C(Zn) = 29.4 at %
• C(Cu) = 70.6 at %

Therefore, the composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu is 29.4 at % and 70.6 at % for Zn and Cu respectively.

Learn more about atomic percent at: brainly.com/question/10018123

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