Answer: v = 3.684 m/s
Explanation: The angular frequency (ω) of a loaded spring is given as
ω = √k/m
Where ω = angular frequency, k =spring constant = 11.9 N/m, m = mass of object = 40.1 g = 0.0401 kg.
The velocity of a simple harmonic motion is defied as
v = ω√A² - x²
Where A = Amplitude = 24.7cm = 0.247m and x = displacement.
For our question, we where asked to find velocity at half way, at half way, x = A/2
Hence at half way, x = 0.247/2 = 0.1235 m.
We need to get the value of angular frequency first.
ω = √(11.9/0.0401)
ω = √296.758
ω = 17.22 rad/s.
Then the velocity is
v = 17.22 √0.247² - 0.1235²
v = 17.22 √0.061009 - 0.01525225
v = 17.22 √0.04575675
v = 17.22 × 0.2139
v = 3.684 m/s
Answer:
The wavelength in the water compared to when its in the air is: 1160 m/s more
~I hope this is correct and has helped you, have a good day/night~
Explanation:
Answer:
19.3
Explanation:
Assuming we have to find Specific gravity of gold.
As we know that specific gravity is defined as the ratio of weight of the object and weight of the water displaced by the object
so it is given by
specific gravity = weight of the object/weight of the water displaced
now we have
weight of the object = (density)(volume)g
weight of object = (19.3)(0.55)g
now weight of the liquid displaced is given by
weight of water displaced = (1 g/cm^3)(0.55ml)g
now we have
specific gravity = (19.3×0.55)/(1×0.55)
specific gravity= 19.3
Given: Force=8000N
displacement= 15 m
W=denotes Work
W= f × d
Substitute Values:
W = 8000 N × 15 m
= 120, 000 Nm
So, the elevator is doing 120, 000 Joule.
( Joule is the SI unit of work)