determine the ph at the equivalence point for the titration of a 40.0 ml sample of 0.100 mhno2 by 0.200 mkoh . (the pka of nitro
1 answer:
pH at the equivalence point is 3.60
<h3>Define pH.</h3>pH is a numerical indicator of how acidic or basic aqueous or other liquid solutions are. The phrase, which is frequently used in chemistry, biology, and agronomy, converts the hydrogen ion concentration, which typically ranges between 1 and gram-equivalents per liter, into numbers between 0 and 14. The hydrogen ion concentration in pure water, which has a pH of 7, is
gram-equivalents per liter, making it neutral (neither acidic nor alkaline). A solution with a pH below 7 is referred to as acidic, and one with a pH over 7 is referred to as basic, or alkaline.
given that,
HNO2 = 0.100M
KOH= 0.200M
pKa = 3.34
using formula,
pH = pKa + log (salt /acid)
= 3.34 + log (0.200/0.100)
= 3.34 + log 2
= 3.34 + 0.30
= 3.60
pH at the equivalence point is 3.60
Learn more about hydrogen ion concentration here:-
#SPJ4
You might be interested in
Answer: The empirical formula is .
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of = 12.24 g
Mass of = 2.505 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 12.24 g of carbon dioxide, = of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 2.505 g of water, = of hydrogen will be contained.
Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of H=
Moles of O=
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For O =
The ratio of C : H : O = 3: 3: 1
Hence the empirical formula is .
Answer:
"2.48 mole" of H₂ are formed. A further explanation is provided below.
Explanation:
The given values are:
Mole of Al,
= 3.22 mole
Mole of HBr,
= 4.96 mole
Now,
(a)
The number of mole of H₂ are:
⇒
or,
⇒
⇒
⇒
(b)
The limiting reactant is:
=
(c)
The excess reactant is:
=