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2 years ago

Write the formula for a complex formed between zn2 zn2 and nh3nh3 with a coordination number of 3.

1 answer:

3 0

Triammine zinc sulfate is the formula for a compound produced between zn2 and nh3 with a coordination number of 3.

<h3>Steps</h3>

Zinc atoms are present in the +2 oxidation state in zinc sulfate (ZnSO4).

Thus, a coordination complex formed by three ammonia ligands and zinc sulfate can be shown below.

NH3 + ZnSO4 = [Zn(NH3)] SO4

In its ionic form, this equation can be expressed as

Zn²⁺ + 3NH₃ = [Zn(NH₃)₃]²⁺

<h3>Coordination number: what is it?</h3>

The number of atoms, ions, or molecules that a central atom or ion in a complex, coordination compound, or crystal holds as its closest neighbors.

<h3>What is a good illustration of a coordination number?</h3>

For instance, [Cr(NH3)2Cl2Br2] has the core cation Cr3+, which is referred to as hexacoordinate and has a coordination number of 6.

learn more about coordination number here

brainly.com/question/12498196

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What is the volume of 12.0 grams of oxygen gas at STP<br><br> Atomic mass:O = 15.99 grams/moles

strojnjashka [21]

Answer:

16.82 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 1.0 atm, STP conditions).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = mass/molar mass = (12.0 g)/(15.99 g/mol) = 0.7505 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 0.0°C + 273 = 273.0 K, STP conditions).

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4 years ago

Which metal most likely conducts electricity best? aluminum copper

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3 years ago

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How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g

Serhud [2]

<u>Answer:</u> The energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

<u>Explanation:</u>

First we have to calculate the mass defect $(\Delta m)$ .

The equation for the alpha decay of thorium nucleus follows:

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Ra}+m_{He})-(m_{Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

(Conversion factor: $1amu=1.66\times 10^{-27}kg$ )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$E=2.0916\times 10^{-13}J$

The energy released for 230 grams of decay of thorium is $2.0916\times 10^{-13}J$

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = $2.0916\times 10^{-13}J$

Then, 3 grams of Th will release energy of = $\frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J$

Hence, the energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

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3 years ago

In the PhET simulation window, click the radio button labeled Mystery in the Blocks menu on the right-hand side of the screen. U

Yuliya22 [10]

Answer:

B, D, E, C, A

Explanation:

We have 5 blocks with their respective masses and volumes.

Block Mass Volume

A 65.14 kg 103.38 L

B 0.64 kg 100.64 L

C 4.08 kg 104.08 L

D 3.10 kg 103.10 L

E 3.53 kg 101.00 L

The density (ρ) is an intensive property resulting from dividing the mass (m) by the volume (V), that is, ρ = m / V

ρA = 65.14 kg / 103.38 L = 0.6301 kg/L

ρB = 0.64 kg / 100.64 L = 0.0064 kg/L

ρC = 4.08 kg / 104.08 L = 0.0392 kg/L

ρD = 3.10 kg / 103.10 L = 0.0301 kg/L

ρE = 3.53 kg / 101.00 L = 0.0350 kg/L

The order from least dense to most dense is B, D, E, C, A

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3 years ago