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PSYCHO15rus [73]
1 year ago
10

Why is it important to compare the positive and negative test results with those of known compounds?

Chemistry
1 answer:
maks197457 [2]1 year ago
5 0

It is important to compare the positive and negative test results with those of known compounds as positive results indicate the presence of that known compound and negative results indicate the absence of that compound which is used for reference.

<h3>What is qualitative analysis?</h3>

Qualitative chemical analysis is a method to determine the chemical composition of a sample.

There are two types of qualitative analysis:

  • Organic Qualitative analysis: It helps in determining the chemical bonds and functional groups in a sample
  • Inorganic qualitative analysis: It helps in determining the ions in the given sample

There are seven ways to analyze a sample qualitatively, which are

  • Change in color
  • Flame test
  • Distillation
  • Extraction
  • Precipitation
  • Chromatography
  • Spectroscopy

A reference compound is always used to which results are compared.

A Positive result indicates that the reference compound is present in the sample whereas a negative result indicates that the reference compound is absent in the given sample.

Learn more about qualitative analysis:

brainly.com/question/1779681

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Answer:

a)  After the balloon inflated after 440 uL of dropwise due to the reaction of 1-Decene and the solution in the conical vial. b) 4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7} c) No H_{2} was not the limiting reactant.

Explanation:

Generally, hydrogenation is the chemical reaction between a compound or element and molecular hydrogen in the presence of catalysts such as platinum.

a) After the balloon inflated after 440 uL of dropwise 1-Decene solution was added due to the reaction between 1-Decene and the solution in the conical vial.

b)  4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7}

c) H_{2} was not the limiting reactant based on the mol to mol ratio of H_{2} and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of H_{2} would also be produced.

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The value of ka for benzoic acid is 6.30×10-5. what is the value of kb, for its conjugate base, c6h5coo-?
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