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omeli [17]
1 year ago
8

If you have a mixture that contains the solid benzoic acid mixed with a volatile alkyl halide liquid. what is the most efficient

technique to separate these two components?
Physics
1 answer:
Goryan [66]1 year ago
6 0

Fractional distillation is the most efficient technique to separate solid benzoic acid mixed with a volatile alkyl halide liquid components.

<h3>Fractional distillation :</h3>

Separating a mixture into its constituent parts, or fractions, is known as fractional distillation. Chemical compounds are separated by heating chemical mixtures to a temperature at which one or more fractions of the mixture evaporate. Distillation is used to fractionate.

Boiling a mixture of liquids results in vapors rising up a glass tube known as a "fractionating column," which is followed by separation. The fractionating column, which is placed between the flask holding the mixture and the "Y" adaptor, improves the separation of the liquids being distilled.

<h3>Uses of fractional distillation :</h3>

Alcohol purification, desalination, crude oil refinement, and the creation of liquefied gases from air are all applications of distillation.

To know more about purification visit :

brainly.com/question/3130146

#SPJ4

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Take into account that density and relative density are given by:

\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

The density of water in kg/m^3 is 1000 kg/m^3.

Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:

1 m^3 = 1000000 ml

1 kg = 1000 g

Then, you obtain the following results:

Brass:

\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}

Cooper:

\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}

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Answer:

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