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Verizon [17]
3 years ago
8

What do parallel circuits and series circuits have in common

Physics
1 answer:
Sonbull [250]3 years ago
7 0
Voltage of each component is same.
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What is a permanent magnet​
Wewaii [24]

Answer:

a magnet that retains its magnetic properties in the absence of an inducing field or current

6 0
3 years ago
Each of the following statements is related to conductors in electrostatic equilibrium. Choose the words that make each statemen
Alexxandr [17]

Answer:

a) interior,  b) inside,   c) minor

Explanation:

In this exercise you are asked to select the correct words so that the statements have been correct

Electric charges always repel each other when they are of the same sign, in conductors this has the consequence that charges accumulate on the surface and the interior remains without electric charges.  with this we analyze the statements

a) interior

b) inside

c) minor

therefore the phrase would be:

(a) The net charge is always zero ---INTERIOR--- the surface of an isolated conductor.

(b) The electric field is always zero ---INSIDE--- a perfect conductor.

(c) The charge density on the surface of an isolated, charged conductor is highest where the surface is ---MINOR---to)

8 0
3 years ago
Create a file "parts_inv.dat" that stores on each line a part number, cost, and quantity in inventory, in the following format:1
andriy [413]

Answer:

%Open the file.

fID = fopen('parts_inv.dat');

%Read from the file.

data = fscanf(fID,'%d\t%f\t%d',[3,inf]);

%Close

fclose(fID);

%Restore the data.

data = data';

%Get the size

[rs, cs] = size(data);

%Set value.

invCost = 0;

%Loop

for rw = 1 : rs

%Find cost

invCost = invCost + (data(rw, 2) * data(rw, 3));

%Loop end

end

%Display the cost.

fprintf('Total cost: %4.2f\n\n', invCost);

Explanation:

7 0
4 years ago
A dynamite blast at a quarry launches a rock straight upward, and 1.7 s later it is rising at a rate of 17 m/s. Assuming air res
Shtirlitz [24]

Answer:

(a) v_0= 34m/s

(b) v=14m/s

Explanation:

We can derive the initial speed of the rock from the equation of the speed in function of the time:

v=v_0-gt\\\\\implies v_0=v+gt

Using the given values for the speed at time t=1.7s, we get:

v_0=17m/s+(9.8m/s^{2})(1.7s)=34m/s

In words, the speed of the rock at launch is 34m/s (a).

Next, we use this to calculate the speed at t=4.9s:

v=v_0-gt\\\\v= 34m/s-(9.8m/s^{2})(4.9s)=-14m/s

This means that the speed of the rock at 4.9s after the launch is 14m/s (b), and the negative sign means that it is moving downwards.

3 0
3 years ago
Differentiate metal nonmetal and metalloids on the basis of physical and chemical properties​
sashaice [31]

Answer:     hi how re u ??

Explanation:

4 0
3 years ago
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