All categories

3 years ago

What do parallel circuits and series circuits have in common

Physics

1 answer:

Sonbull [250]3 years ago

7 0

Voltage of each component is same.

You might be interested in

The owner of a van installs a rear-window lens that has a focal length of -0.304 m. When the owner looks out through the lens at

Naddika [18.5K]

Answer:

$p =-1.03$

Explanation:

From the question we are told that:

Focal length of lens $f=-0.304 m$

Image distance $q=0.237 m$

Height of image $H_i=0.343$

Generally the lens equation is mathematically given by

$\frac{1}{f} = \frac{1}{q} - \frac{1}{p}$

Where $p$ is Subject

$p = \frac{(qf) }{(f - q)}$

$p = \frac{(-0.237)(-0.304)) }{((-0.304) - (0.237))}$

$p =-1.03$

Therefore the distance between the person and the car is

$p =-1.03$

7 0

3 years ago

What is the ionosphere

ICE Princess25 [194]

A ionosphere is a layer of the earths atmosphere that is ionized by solar and cosmic radiation <span />

7 0

4 years ago

Calculate the current through the ammeter (look at photo)

AleksAgata [21]

Answer:

6 amps

Explanation:by Kirchhoff's loop rule the current at any point in the loop must be equal or charge would be building up. The current at the ammeter is equally to the total current through the sun of the paths in parallel which it is in series with

8 0

2 years ago

Please help me with this physics question!

Vadim26 [7]

Not sure about the answer

7 0

4 years ago

A 1.00 kg solid, uniform disk rolls without slipping across a level surface, translating at 3.00 m/s. If the disk's radius is 0.

cluponka [151]

Explanation:

Given that,

Mass of the disk, m = 1 kg

Translational speed of the disk, v = 3 m/s

Radius of the disk, r = 0.39 m

(a) Let K is the tranlational kinetic energy of the disk. Its formula is given by :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 1\times 3^2$

K = 4.5 J

(b) Let K' is the rotational kinetic energy of the disk. Its formula is given by :

$K'=\dfrac{1}{2}I\omega^2$

$K'=\dfrac{1}{2}\dfrac{mr^2}{2}(\dfrac{v}{r})^2$

$K'=\dfrac{1}{4}mv^2$

$K'=\dfrac{1}{4}\times 1\times 3^2$

K' = 2.25 J

Hence, this is the required solution.

5 0

3 years ago