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Luba_88 [7]
1 year ago
14

When a nonmetal oxide reacts with water, it forms an oxoacid with the same oxidation number as the nonmetal. Give the name and f

ormula of the oxide used to prepare each of these oxoacids:
(a) hypochlorous acid;
Chemistry
1 answer:
vaieri [72.5K]1 year ago
5 0

Addition of chlorine to water gives both hydrochloric acid (HCl) and hypochlorous acid (HClO)

What are Transition metal oxides ?

Transition metal oxides (TMOs) are another class of nanomaterials, frequently used as anode in alkaline batteries due to their distinctive properties such as abundant active sites, short diffusion pathways, low preparation cost, high theoretical capacity and distinct reaction mechanism.

Cl2 + H2O ⇌ HClO + HCl

Cl2 + 4 OH− ⇌ 2 ClO− + 2 H2O + 2 e−

Cl2 + 2 e− ⇌ 2 Cl−

The acid can also be prepared by dissolving dichlorine monoxide in water; under standard aqueous conditions, anhydrous hypochlorous acid is currently impossible to prepare due to the readily reversible equilibrium between it and its anhydride.

2 HClO ⇌ Cl2O + H2O      K (at 0 °C) = 3.55×10−3 dm3 mol−1

The presence of light or transition metal oxides of copper, nickel, or cobalt accelerates the exothermic decomposition into hydrochloric acid and oxygen

2 Cl2 + 2 H2O → 4 HCl + O2

To learn more about exothermic decomposition click on the link below:

brainly.com/question/20089404

#SPJ4

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The answer for the following problem is mentioned below.

  • <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules.</em></u>

Explanation:

Given:

mass of calcium phosphate (Ca_{3}(PO_{4} )_{2} ) = 125.3 grams

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molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = (40×3) + 3 (31 +(4×16))

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = 120 + 3(95)

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<em>We also know;</em>

No of molecules at STP conditions(N_{A}) = 6.023 × 10^23 molecules

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no of molecules present in the sample(N)

We know;

\frac{m}{M} =\frac{N} }{}N÷N_{A}

\frac{405}{125.3} =\frac{N}{6.023*10^23}

N =(405×6.023 × 10^23) ÷ 125.3

N = 19.3 × 10^23 molecules

<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules</em></u>

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