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marta [7]
2 years ago
5

Based on the passage, what is the structure of the product of the reaction between 8-hydroxyquinoline-5 sulfonate and HRP mcat r

eddit
Chemistry
1 answer:
dusya [7]2 years ago
4 0

A because the outcome of this reaction exists a radical formed by the oxidation of an aromatic amine's or phenol's ring substituent. The hydroxyl group of a phenol serves as the ring substituent in this condition.

<h3>Which two enzyme types are required for the two-step process of converting cytosine to 5 hmC?</h3>
  • The methyl group exists moved to cytosine in the first step, and it exists then hydroxylated in the second stage.
  • Thus, a transferase and an oxidoreductase exist as the two groups of enzymes needed.

<h3>Which kind of interaction between proteins and the dextran column material is most likely to take place?</h3>
  • Hydrogen bonding because the glucose's OH would create an H-bond with any disclosed polar side chains on a protein surface.

<h3>Two out of the four proteins would adhere to a cation-exchange column at what buffer pH?</h3>
  • Only positively charged proteins can attach to a cation-exchange column, and this can only occur when the pH exists lower than the pI.
  • Proteins A and B would both be positively charged at pH 7.0.

To learn more about hydroxyquinoline refer to:

brainly.com/question/26102339

#SPJ4

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Convert 0.881 mol N2 at STP to volume in liters ​
Vinvika [58]
The answers will be 21.5 L N2
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son4ous [18]

Answer: The molar enthalpy change is 73.04 kJ/mol

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

moles of HCl= molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol

As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.

volume of water = 100.0 ml + 50.0 ml = 150.0 ml

density of water = 1.0 g/ml

mass of water = volume \times density=150.0ml\times 1.0g/ml=150.0g

q=m\times c\times \Delta T

q = heat released

m = mass  = 150.0 g

c = specific heat = 4.184J/g^0C

\Delta T = change in temperature = 4.83^0C

q=150.0\times 4.184\times 4.83

q=3031.3J

Thus 0.0415 mol of HCl produces heat = 3031.3 J

1 mol of HCL produces heat = \frac{3031.3}{0.0415}\times 1=73043.3J=73.04kJ

Thus molar enthalpy change is 73.04 kJ/mol

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Please answer number12
densk [106]
Hydrogen maybe but I don’t know for sure
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mrs_skeptik [129]

Answer:

The answer to this question is D.

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