Question

a baseball dropped from the roof of a tall building takes 3.1 seconds to hit the ground. how tall is the building? [neglect friction.]

Answer 1

If a baseball dropped from the roof of a tall building takes 3.1 seconds to hit the ground, the height of the building would be 47.1 m.

According to Newton's second law of motion,

$s=ut+\frac{1}{2}at^{2}$

Where, s is the distance covered by the body, u is its initial velocity, t is the time taken by the body, and a is the acceleration of the body.

Here, the distance covered will be equal to the height of the building.

Since the ball was dropped, its initial velocity will be zero.

Also, the acceleration of the ball is the acceleration due to gravity, $g=9.8 m/s^{2}$.

Substituting the values,

$h=0+\frac{1}{2} gt^{2}$

$h=\frac{1}{2} \times9.8\times3.1^{2}$

$h=47.1m$

Therefore, the height of the building would be 47.1 m.

Learn more about Newton,s laws of motion here:

brainly.com/question/18730057

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