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Vaselesa [24]
1 year ago
7

An inorganic compound, when placed in water, dissociates 99orming cations and anions neither of which are:______

Physics
1 answer:
Ivanshal [37]1 year ago
4 0

Neither are Strong acid.

<h3>What does “strong acid” mean?</h3>

In the solution, solid acids entirely separate into ions. For instance, hydrochloric acid is a solid acid.

It totally ionizes, forming hydrogen and chloride ions. Nitric acid and sulfuric acid are also components of strong acids.

A solid or strong acid is one that has completely dissociated into ions. It is a weak acid if it does not dissociate completely.

<h3>What is an example of a strong acid?</h3>

Chloric acid, hydrobromic acid, hydrochloric acid, hydroiodic acid, nitric acid, perchloric acid, and sulfuric acid are the seven major acids that make up strong acids. These are referred to as strong acids since they can totally dissociate in water.

To know more about strong acid visit:

brainly.com/question/16749233

#SPJ4

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A boat is traveling with a velocity of 18 meters/second relative to water and the river is flowing at a velocity of 2.5 meters/s
ddd [48]
Vt = Vboat - Vriver 
Vt = 18 - 2.5 = 15.5 m/s 

If the boat's direction is the same as the water, you sum the velocities of the river and the boat . 
8 0
3 years ago
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It is easier to overcome load when the load is shifted towards the wheel in a wheelbarrow why ? give reason​
krok68 [10]

Answer:

The wheelbarrow's wheel and axle help the wheelbarrow to move without friction thus making it easier to push or pull. That's why it will be easier to lift a load in wheel barrow of the load is transferred towards the wheel.

4 0
3 years ago
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A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is
Aleksandr [31]

Answer:

The acceleration of the crate is 1.8 m/s² so the answer is a.

Explanation:

The very first thing you must do when solving this problem is to draw a free body diagram. (The body diagram is attached to this answer)

So once we got the free body diagram, we can analyze it and build our sum of forces in the x and y directions. Notice that according to the diagram, there are 4 forces to this problem, Normal (N), Weight (W), kinetic friction (fk) and the 750N force.

As one may see in the free body diagram, two of the forces are vertical forces: N and W, so we can use them to build a sum of forces:

Starting with the sum of forces in the y-direction, we get:

ΣF_{y}=0

We set the sum equal to zero because there is no movement in the y-direction, so the system is in vertical equilibrium.

so the sum will be:

N-W=0

when solving for N we get that:

N=W

where W is found by multiplying the mass of the crate by the acceleration of gravity:

N=250kg*9.8m/s²

N=2450N

Once we found the normal force, we can use it to find the kinetic friction which is given by the following formula:

f_{k}=Nμ

where μ is the kinetic friction coefficient.

So we get that the kinetic friction is:

f_{k}=2450N*0.12

so

f_{k}=294

With this information we can go ahead and find the sum of horizontal forces:

ΣF_{x}=ma

In this case the sum is equal to mass times acceleration because the crate is moving horizontally due to the action of a force, so it will have an acceleration.

so the sum of forces look like this:

750N-f_{k}=ma

so

750N-294N=(250kg)a

when solving for a we get:

a=\frac{759N-294N}{250kg}\\ \\a=1.8m/s^{2}

so the crate's acceleration is 1.82m/s².

5 0
3 years ago
What is one watt ? Write the relation of watt with kilowatt , megawatt , and horsepower .​
alina1380 [7]

Answer:

See the explanation below

Explanation:

The watt (the power) is equal to the relationship between the work and the time in which that work is performed.

P = W/t

where:

W = work [J] (units of Joules)

t = time [s].

Now 1000 [W] are equal to 1 [kW]

And 1000000 [W] are equal to 1 [MW]

The horsepower is the unit of power in the imperial system of units.

And 745.7 [W] are equal to 1 [Hp]

3 0
3 years ago
Match each description to its written source.
madreJ [45]
1=6, 2=8
I hope this helped

3 0
3 years ago
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