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Yuri [45]
1 year ago
12

What is the number of molecules in 500m cube of Oxygen at room temperature

Chemistry
1 answer:
d1i1m1o1n [39]1 year ago
5 0

4.95 is the number of molecules in 500m cube of Oxygen at room temperature and pressure

we have got data

pressure=1atm

temperature=298 k

volume=500 m^3

gas constant, R=8.31

now, by applying ideal gas equation

PV=nRT

1×500=n×8.31×298

n=2476.38/500

n=4.95

It is the lowest part of the material and has chemical elemental properties. Atoms do not independently exist; rather, they combine to form ions and molecules, which then combine to form the material that we can see, feel, and touch.

Molecules are made up of one or more atoms connected by covalent (chemical) connections. Atoms can be visualized as circles with a nucleus in the center (made up of protons and neutrons) and one or more concentric circles around it that indicate the "shells" or "levels" in which the electrons surrounding the atom's nucleus are located, as well as markings that identify the electron. each level

To know more about  molecules visit : brainly.com/question/11405437

#SPJ9

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alexandr402 [8]

Answer:

A. The concentration of H+ is 0.0025 M

B. The pH is 2.6

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Explanation:

We'll begin by writing the balanced

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HClO4 —> H+ + ClO4-

A. Determination of the concentration of H+ in 0.0025 M HClO4. This is illustrated below:

From the balanced equation above,

1 mole of HClO4 produced 1 mole of H+.

Therefore, 0.0025 M of HClO4 will also produce 0.0025 M of H+.

The concentration of H+ is 0.0025 M

B. Determination of the pH.

The pH of the solution can be obtained as follow:

The concentration of H+, [H+]

= 0.0025 M

pH =?

pH = - log [H+]

pH = - log 0.0025

pH = 2.6

C. Determination of the concentration of OH-

To obtain the concentration of OH-, we must first calculate the pOH of the solution. This is illustrated below:

pH + pOH = 14

pH = 2.6

pOH =?

pH + pOH = 14

2.6 + pOH = 14

Collect like terms

pOH = 14 - 2.6

pOH = 11.4

Now, we can calculate the concentration of the OH- as follow:

pOH = - Log [OH-]

pOH = 11.4

11.4 = - Log [OH-]

- 11.4 = log [OH-]

[OH-] = anti log (- 11.4)

[OH-] = 3.98x10^-12 M

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hram777 [196]

Answer:

Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.

Explanation:

Step 1: data given

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Step 2: The balanced equation

Mg(OH)2(s)  ⇄ Mg2+(aq) + 2OH-(aq)

Step 3: Define the equilibrium constant Kc

Kc = [OH-]²[Mg^2+]

Pure solids and liquids do not have any effect or influence on the equilibrium in the reaction. So they are not included in the equilibrium constant expression.

This means Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.

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Answer:

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