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Gelneren [198K]
1 year ago
15

caffeine is the active ingredient in coffee, tea, and some carbonated beverages. add lone pairs, as needed, to the structure of

caffeine.
Chemistry
1 answer:
lawyer [7]1 year ago
5 0

Here we add lone paris,to the structure of caffeine.

<h3>What is caffeine?</h3>

Caffeine is a type of drug. It is used as a cognitive inhancer.

We've been looking at then following structure. We definitely would like to look at it is the  geometries of some of the centers. We'll look to it  geometry here. Yes, yeah. Down here as well. We have a bonding angle of less than 107.5 because we have a trig onal planer with a bonding angle of 120. This is the  site has a geometry with all the  bounding angles of 109.5. it is the  funding angles of less than 107.5 carbon site here and less than 120 carbon site of  here are the tribunal to the  parameters. My substitute if luck with the has the same geometry with bonding angles as before.

To know more about caffeine click-

brainly.com/question/17357865

#SPJ1

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WILL GIVE BRANLIEST!! EASY BUT I WAS TO LAZY TO LEARN!! WILL FOREVER BE GREATFUL!!! WILL GIVE BRANLIEST!! EASY BUT I WAS TO LAZY
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Answer:

3. Which side of the chain should you count from when naming organic compounds?

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3 0
3 years ago
1 How is the density of a substance calculated? 
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4 0
3 years ago
enny places a strip of pH paper into a solution. When she removes the pH paper, it has turned yellow-green. What should Jenny do
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8 0
4 years ago
From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp
Nina [5.8K]

<u>Answer:</u> The concentration of NH_3 required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of NiC_2O_4, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of NiC_2O_4 = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M

For the given chemical equations:

NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}

Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9

Net equation: NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?

To calculate the equilibrium constant, K for above equation, we get:

K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48

The expression for equilibrium constant of above equation is:

K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}

As, NiC_2O_4 is a solid, so its activity is taken as 1 and so for C_2O_4^{2-}

We are given:

[[Ni(NH_3)_6]^{2+}]=0.016M

Putting values in above equations, we get:

0.48=\frac{0.016}{[NH_3]^6}}

[NH_3]=0.285M

Hence, the concentration of NH_3 required will be 0.285 M.

7 0
3 years ago
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