A skateboarder with a mass of 67.0 kilograms (including the skateboard) rolls down from the top of a ramp, reaching a velocity o
f 7.30 meters per second at the bottom of the ramp. Assuming friction is 0, what was the potential energy of the skateboarder at the top of the ramp?
1,785 J.
59.70 J.
74.30 J.
489.1 J.
1,785 J.
59.70 J.
74.30 J.
489.1 J.
1 answer:
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Answer:
ω₂ = 1.9025 x 10⁻⁶ rad/s
Explanation:
given,
mass of star = 1.61 x 10³¹ kg
angular velocity = 1.60 x 10⁻⁷ rad/s
diameter suddenly shrinks = 0.29 x present size
r₂ = 0.29 r₁
using conservation of angular momentum
I₁ ω₁ = I₂ ω₂
ω₂ = 1.9025 x 10⁻⁶ rad/s
Answer:
The amount of work done in order to lift the box is
Explanation:
Given the weight of each box is
And the man lifts boxes at a height of
We need to find the amount of work done.
The amount of work done is the product of applied force that causes the displacement
.
In our problem force is and displacement is
.
Now, work done
So, the amount of work done in order to lift the box is