Question

humans evolved in earth's atmosphere, therefore the pressures interior to the body are relatively close to atmospheric pressure. because the differences between internal body pressures and atmospheric pressure are so small, individuals have a difficult time gauging the magnitude of atmospheric pressure. suppose an individual is lying on his stomach with sheets of paper stacked on his back. if each sheet of paper has a mass of 0.004400.00440 kg and is the standard letter size of 8.5 in8.5 in by 11 in11 in ( 0.216 m by 0.279 m0.216 m by 0.279 m ), how many sheets must be stacked to produce a pressure on his back equal to atmospheric pressure (roughly 101325 pa101325 pa )?

Answer 1

A total of 151988 sheets of paper are required to be put on the individual so that it create a pressure of 1 atm.

We know that the pressure is given by the force applied on the area divided by the magnitude of the area.

Here, it is given that dimensions of the paper is 8.5 inch X 11 inch.

So the area of the paper is 93.5 in².

Converting inch square into metre square,

Area = 0.06m².

The mass of 1 sheet of paper is 0.004 kg.

So the force applied by the sheet of paper on the person will be equal to,

F = 0.004 × 10

F = 0.04 N.

Let us say that n number of sheets are required.

The pressure that is needed to be created is 101325 pascals.

Now,

Pressure = force/area

Putting the values,

101325 = N(0.04)/0.06

N = 151988.

So, total of 151988 sheets are required.

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