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Nostrana [21]
1 year ago
11

A one dimensional array data is declared as follows: char data[4]; the base address is 2222 and each value takes up one location

in memory. what is the address of the fourth element?
Physics
1 answer:
andrezito [222]1 year ago
3 0

The correct answer for the address of the fourth element will be 2225.

The fourth element will be data -.

So if the data[0] element starts at 2222, and each char element takes 1 byte, then

data[0] starts at 2222

data[1] starts at 2223

data[2] starts at 2224

data[3] starts at 2225

Answer: 2225

A linear data structure that collects elements of the same data type and stores them in contiguous and adjacent memory locations is known as an array. Arrays use an index system that ranges from 0 to (n-1), where n is the array's size.

The array data type is a compound data type represented in the database dictionary by the number 8. Arrays are collections of elements of the same data type that are accessed via an index (attribute) number. The terms array, list, vector, and sequence are all synonymous

Learn more about array data here :-

brainly.com/question/23611240

#SPJ4

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The volume of water in the Pacific Ocean is about 7.00 × 108 km3. The density of seawater is about 1030 kg/m3. For the sake of t
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The concepts used to solve this exercise are given through the calculation of distances (from the Moon to the earth and vice versa) as well as the gravitational potential energy.

By definition the gravitational potential energy is given by,

PE=\frac{GMm}{r}

Where,

m = Mass of Moon

G = Gravitational Universal Constant

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First we calculate the mass through the ratio given by density.

m = \rho V

m = (1030Kg/m^3)(7*10^8m^3)

m = 7.210*10^{11}Kg

PART A) Gravitational potential energy of the Moon–Pacific Ocean system when the Pacific is facing away from the Moon

Now we define the radius at the most distant point

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Then the potential energy at this point would be,

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PE_1 = \frac{(6.61*10^{-11})*(7.21*10^{11})*(7.35*10^{22})}{3.904*10^8}

PE_1 = 9.05*10^{15}J

PART B) when Earth has rotated so that the Pacific Ocean faces toward the Moon.

At the nearest point we perform the same as the previous process, we calculate the radius

r_2 = 3.84*10^8-6.4*10^6 - 3.776*10^8m

The we calculate the Potential gravitational energy,

PE_2 = \frac{GMm}{r_2}

PE_2 = \frac{(6.61*10^{-11})*(7.21*10^{11})*(7.35*10^{22})}{3.776*10^8}

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Answer:

Es útil porque al saberlo evitas sobrexponerte a problemas como <em><u>enfermedades, desgarros o daños a largo plazo de tu cuerpo.</u></em>

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