1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Snowcat [4.5K]
1 year ago
5

what happens to the frequency the centripetal force on an object in circular motion is doubled while the object keeps the same r

adius of rotation
Physics
1 answer:
kondaur [170]1 year ago
3 0

The new frequency also double the centripetal force on an object in circular motion is doubled while the object keeps the same radius of rotation.

The mass of the object is m .

The radius of the circle is r.

The new centripetal force F2 = 2F1 .

A force that causes a body to follow a curved path is known as a centripetal force, which derives from the Latin words centrum, "Centre," and petered, "to pursue." It always moves in a direction that is the opposite of the body's motion and in the direction of the fixed point of the path's immediate Centre of curvature. "A force by which bodies are dragged or driven, or in any other manner tend, towards a point as to a Centre," was how Isaac Newton defined it. The centripetal force that causes astronomical orbits in Newtonian physics is provided by gravity.

The scenario in which a body moves uniformly fast along a circular path is one frequent example of centripetal force. Towards the Centre of the object, the centripetal force is directed along the radius and at an angle to the velocity.

Learn more about centripetal force  here:

brainly.com/question/11324711

#SPJ4

You might be interested in
Which property makes radio waves most useful for communication? They have low frequencies. They have long wavelengths. They tran
Mila [183]
I think it would be that they have long wavelengths
6 0
3 years ago
Read 2 more answers
a bubble of air of volume 1cm^3 is released by a deep sea diver at a depth where the pressure is 4.0 atmospheres. assuming its t
lys-0071 [83]

Answer:

hope this helps!

Explanation:

Volume of the air bubble, V1=1.0cm3=1.0×10−6m3

Bubble rises to height, d=40m

Temperature at a depth of 40 m, T1=12oC=285K

Temperature at the surface of the lake, T2=35oC=308K

The pressure on the surface of the lake: P2=1atm=1×1.103×105Pa 

The pressure at the depth of 40 m: P1=1atm+dρg

Where,

ρ is the density of water =103kg/m3

g is the acceleration due to gravity =9.8m/s2

∴P1=1.103×105+40×103×9.8=493300Pa

We have T1P1V1=T2P2V2

Where, V2 is the volume of the air bubble when it reaches the surface.

V2=

8 0
3 years ago
Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t
ziro4ka [17]

Answer:

(a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

Explanation:

Given that,

Rotation = 20.0 times

Time = 5.00 sec

We need to calculate the angular frequency

Using formula of angular frequency

\omega_{i}=20\times\dfrac{2\pi}{T}

put the value into the formula

\omega_{i}=20\times\dfrac{2\pi}{5.00}

\omega_{i}=8.00\pi

We need to calculate the angular displacement

Using formula of  angular displacement

\theta=6\times2\pi=12\pi

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}^2-\omega_{i}^2=2\alpha\times\theta

0-64\pi^2=2\times12\pi\times\alpha

\alpha=-\dfrac{64\pi^2}{24\pi}

\alpha=-8.3\ rad/s^2

Negative sign shows the opposite direction of the motion.

The acceleration is 8.3 rad/s².

We need to calculate the time

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha\times t

0-8\pi=-8.3t

t=\dfrac{8\pi}{8.3}

t=3.0\ sec

The time is 3.0 sec.

Hence, (a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

4 0
3 years ago
Please can someone answer this question ​
EastWind [94]
B????????? I thinkkkkk
7 0
3 years ago
Read 2 more answers
Determine the centripetal force upon a 40-kg child who makes 10 revolution around the cliffhanger in 29.3 seconds.the radius of
zysi [14]

Answer:

The centripetal force acting on the child is 39400.56 N.

Explanation:

Given:

Mass of the child is, m=40\ kg

Radius of the barrel is, R=2.90\ m

Number of revolutions are, n =10

Time taken for 10 revolutions is, t=29.3\ s

Therefore, the time period of the child is given as:

T=\frac{n}{t}=\frac{10}{29.3}=0.341\ s

Now, angular velocity is related to time period as:

\omega=\frac{2\pi}{T}=\frac{2\pi}{0.341}=18.43\ rad/s

Now, centripetal force acting on the child is given as:

F_{c}=m\omega^2 R\\F_{c}=40\times (18.43)^2\times 2.90\\F_{c}=40\times 339.66\times 2.90\\F_{c}=39400.56\ N

Therefore, the centripetal force acting on the child is 39400.56 N.

8 0
3 years ago
Other questions:
  • A 6.0-ohm resistor that obeys Ohm’s Law is connected to a source of variable potential difference. When the applied voltage is d
    8·1 answer
  • Why is there no electric field at the center of a charged spherical conductor?
    7·1 answer
  • Which of the following statements about Ohm’s Law is true?
    15·2 answers
  • 1 kilogram equals how many grams
    8·1 answer
  • First, design an experiment you could conduct that might measure how thermal equilibrium occurs. What materials would you use? W
    8·1 answer
  • Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This
    12·1 answer
  • Prototypes rely on which of the following?
    7·1 answer
  • In winter the air just above the top bunk of a bunk bed is warmer than the air just above the bottom bunk because warm air rises
    9·1 answer
  • The design of interior spaces is relatively unimportant to good<br> architecture?
    7·1 answer
  • Use the data to answer the question.<br><br><br><br> Which statement best describes the data?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!