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kotykmax [81]
1 year ago
8

an electron accelerated from rest through a voltage of 770 v enters a region of constant magnetic field. part a if the electron

follows a circular path with a radius of 18 cm , what is the magnitude of the magnetic field?
Physics
1 answer:
finlep [7]1 year ago
3 0

The magnitude of the magnetic field on which an electron accelerated from rest through a voltage of 770v enters a region of constant magnetic field is 3.744 * 10^{-4} T

From the conservation of energy, we have

\frac{1}{2}mv^{2}  =qV

v=\sqrt{\frac{2qV}{m} }

=\sqrt{\frac{2*(1,6 * 10^{-19})(770) }{9.11 * 10^{-31} } }

=1.644*10^{7m/s

At Equilibrium, Centripetal force = magnetic force

\frac{mv^{2} }{r}=Bqv

B=mv/rq

by putting, m=9.11* 10^-31 kg

v=1.664*10^7m/s

r=25*10^-2m

q=1.6*10^-19 C

We get, B=3.774* 10^-4 T

Hence the magnitude of the magnetic field, B=3.774* 10^-4 T

Learn more about Magnetic Field here:

brainly.com/question/23096032

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An aluminum bar has a mass of 9 kg in the air. Calculate its volume. Now imagine that you submerge the aluminum bar in water han
yan [13]

Answer:

55.7 N

Explanation:

The density of aluminum is 2710 kg/m³.  So its volume is:

V = (9 kg) / (2710 kg/m³)

V = 0.00332 m³

The apparent weight is the actual weight minus the buoyant force.

N = mg − B

N = mg − ρVg

N = g (m − ρV)

N = (9.8 m/s²) (9 kg − (1000 kg/m³) (0.0332 m³))

N = 55.7 N

7 0
3 years ago
The number of times that a wave vibrates in unit is called
kari74 [83]
I believe it's frequency. 
6 0
4 years ago
A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east​
elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: 56.31^o

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\

Now we can find the value of the angle by using the arctan function:

tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o

6 0
3 years ago
10 kg mass sliding along a horizontal rough surface at speed 30 m/s and rests in 6 seconds. what is the coefficient of friction
Aleks [24]

The coefficient of friction is 0.5.

<h3>What is Coefficient of friction?</h3>

The ratio of friction force to normal force is known as the coefficient of friction (COF), which has no dimensions. Those materials are said to as lubricous if their COF is less than 0.1. Surface roughness and COF are dependent on the composition of the materials.

Initial velocity, u=30m/s

time taken = 6s

Final velocity, v=0

Acceleration of friction, a=μg=10μms⁻²

Apply first kinematic equation of motion,

v - u = at

0 - 30 = (-10μms⁻²) × 6

-30 = -60μ

μ = 1/2

μ = 0..5  

Hence, coefficient of friction is 0.5

to learn more about Coefficient of friction go to - brainly.com/question/14121363

#SPJ4

7 0
2 years ago
2. What is the momentum of a 9-kg object moving at -1.5 m/s?/
Alla [95]

Answer:13.5kgm/s

Explanation:

mass=9kg

Velocity=1.5m/s

Momentum=mass x velocity

Momentum=9 x 1.5

Momentum=13.5kgm/s

4 0
4 years ago
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