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vaieri [72.5K]
11 months ago
13

How is the free energy change of a process related to the work that can be obtained from the process? Is this quantity of work o

btainable in practice? Explain.
Chemistry
1 answer:
nevsk [136]11 months ago
7 0

Free energy is used to determine how systems change and how much work they can produce.

If the free energy of the reactants is greater than that of the products, the entropy  will increase when the reaction takes place  so the reaction will tend to take place spontaneously. If the free energy of the products exceeds that of the reactants, then the reaction will not take place

The Gibb's free energy change (ΔG) is:

ΔG<0⟶ Spontaneous process

ΔG>0⟶  Non-spontaneous process

ΔG=0⟶ Equilibrium process or reversible process

Gibb's free energy is a quantity used to measure the maximum amount of work done in a thermodynamic system , when the temperature and pressure are constant .

It is a state function hence it doesn't depend on path .

ΔG = ΔH - T(ΔS)

Learn more about free energy here :

brainly.com/question/10012881

#SPJ4

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8. Which type of element requires the least amount of energy to remove an electron?​
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Answer:

nonmetals

Explanation:

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2 years ago
How long does it take electrons to get from the car battery to the starting motor? Assume the current is 137 A and the electrons
WARRIOR [948]

Answer:

t = 55.79 min

Explanation:

First, the problem is asking for calculate the time that it takes electrons from the battery to the motor.

The general formula to calculate time is:

<em>t = d/V (1)</em>

Where:

d: distance or length

V: speed

Now, we don't have data of speed, but we can know an expression of current density in function of the distance which is the following:

<em>J = n*q*V (2)</em>

Where:

q: charge of the particle (1.6x10^-19 C)

n: number of charge carriers per unit of volume

Current density (J) is actually current per Area so:

<em>J = I/A (3)</em>

Replacing (3) in (2) we have:

I/A = nqV

Solving for V:

<em>V = I/Anq (4)</em>

Finally, if we replace this expression in (1) we have:

<em>t = nqAd / I (5)</em>

Now, the value of n, it's not given but it can be calculated because we have mass density, molar mass and avogadro's number, so this value of "n" can be calculated using the following expression:

<em>n = D * Av / MM (6)</em>

Where:

D: mass density (kg/m³)

Av: avogadro number (6.02x10^23 atom/mol)

MM: molar mass (kg/mol)

Putting the data that we know to calculate n we have:

n = 8960 * 6.02x10^23 / 0.0635

n = 8.49x10^28 atom/m³

Now with the value of n, we can finally calculate the time:

<em>t = nqAd / I </em>

A is the area and it should be in m²: 44.6 mm² / 1x10^6 m = 4.46x10^-5 m²

d is the length in meter: 75.7 cm / 100 cm/m = 0.757 m

so replacing these data in (5):

t = 8.49x10^28 * 1.6x10^-19 * 4.46x10^-5 * 0.757 / 137

t = 3,347.63 s

But the answer is in minute so:

t = 3,347.63 / 60

<em>t = 55.79 min</em>

so the electrons takes 56 min aprox. to go from the car battery to the starting motor.

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Which tool was most likely used in a procedure if the lab report shows that approximately 300 mL of water was used?
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Answer:

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