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vaieri [72.5K]
1 year ago
13

How is the free energy change of a process related to the work that can be obtained from the process? Is this quantity of work o

btainable in practice? Explain.
Chemistry
1 answer:
nevsk [136]1 year ago
7 0

Free energy is used to determine how systems change and how much work they can produce.

If the free energy of the reactants is greater than that of the products, the entropy  will increase when the reaction takes place  so the reaction will tend to take place spontaneously. If the free energy of the products exceeds that of the reactants, then the reaction will not take place

The Gibb's free energy change (ΔG) is:

ΔG<0⟶ Spontaneous process

ΔG>0⟶  Non-spontaneous process

ΔG=0⟶ Equilibrium process or reversible process

Gibb's free energy is a quantity used to measure the maximum amount of work done in a thermodynamic system , when the temperature and pressure are constant .

It is a state function hence it doesn't depend on path .

ΔG = ΔH - T(ΔS)

Learn more about free energy here :

brainly.com/question/10012881

#SPJ4

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At which type of tectonic plate boundary is a volcano least likely to occur?
Katena32 [7]

Answer:

A divergent boundary is when the plates move apart from each other. When the plates part, magma from under either plate rises and forms a volcano. A hotspot is the third place a volcano can form. This particular type is the least common.

Explanation:

7 0
3 years ago
Read 2 more answers
CH3COOH  CH3COO– + H+
Oxana [17]

(a)

pH = 4.77

; (b)

[

H

3

O

+

]

=

1.00

×

10

-4

l

mol/dm

3

; (c)

[

A

-

]

=

0.16 mol⋅dm

-3

Explanation:

(a) pH of aspirin solution

Let's write the chemical equation as

m

m

m

m

m

m

m

m

l

HA

m

+

m

H

2

O

⇌

H

3

O

+

m

+

m

l

A

-

I/mol⋅dm

-3

:

m

m

0.05

m

m

m

m

m

m

m

m

l

0

m

m

m

m

m

l

l

0

C/mol⋅dm

-3

:

m

m

l

-

x

m

m

m

m

m

m

m

m

+

x

m

l

m

m

m

l

+

x

E/mol⋅dm

-3

:

m

0.05 -

l

x

m

m

m

m

m

m

m

l

x

m

m

x

m

m

m

x

K

a

=

[

H

3

O

+

]

[

A

-

]

[

HA

]

=

x

2

0.05 -

l

x

=

3.27

×

10

-4

Check for negligibility

0.05

3.27

×

10

-4

=

153

<

400

∴

x

is not less than 5 % of the initial concentration of

[

HA

]

.

We cannot ignore it in comparison with 0.05, so we must solve a quadratic.

Then

x

2

0.05

−

x

=

3.27

×

10

-4

x

2

=

3.27

×

10

-4

(

0.05

−

x

)

=

1.635

×

10

-5

−

3.27

×

10

-4

x

x

2

+

3.27

×

10

-4

x

−

1.635

×

10

-5

=

0

x

=

1.68

×

10

-5

[

H

3

O

+

]

=

x

l

mol/L

=

1.68

×

10

-5

l

mol/L

pH

=

-log

[

H

3

O

+

]

=

-log

(

1.68

×

10

-5

)

=

4.77

(b)

[

H

3

O

+

]

at pH 4

[

H

3

O

+

]

=

10

-pH

l

mol/L

=

1.00

×

10

-4

l

mol/L

(c) Concentration of

A

-

in the buffer

We can now use the Henderson-Hasselbalch equation to calculate the

[

A

-

]

.

pH

=

p

K

a

+

log

(

[

A

-

]

[

HA

]

)

4.00

=

−

log

(

3.27

×

10

-4

)

+

log

(

[

A

-

]

0.05

)

=

3.49

+

log

(

[

A

-

]

0.05

)

log

(

[

A

-

]

0.05

)

=

4.00 - 3.49

=

0.51

[

A

-

]

0.05

=

10

0.51

=

3.24

[

A

-

]

=

0.05

×

3.24

=

0.16

The concentration of

A

-

in the buffer is 0.16 mol/L.

hope this helps :)

6 0
2 years ago
A scientist makes several observations, develops a question, researches what is known about the question, forms a hypothesis, an
Alex73 [517]
The scientist should make a new hypothesis and do a new experiment! That is what I say!
8 0
3 years ago
30 POINTS PLEASE HELP ME I NEED YALL PLEASE
Kay [80]

6CO2 + 6H2O → C6H12O6 + 6O2

glucose produced = 1/6 x 23.6 = 3.93 moles

4 0
2 years ago
Read 2 more answers
Nitrogen gas (N2) and hydrogen gas (H2) react to produce ammonia (NH3).
WINSTONCH [101]

Answer:

I believe it would be 2

Explanation:

if there are 2 nitrogen molecules then there would have to be 2 hydrogen molecules but this could be completely wrong

if this happens to be right, ur welcome :3 here's a Jay Jay pic for u cuz why not

8 0
3 years ago
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