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vaieri [72.5K]
11 months ago
13

How is the free energy change of a process related to the work that can be obtained from the process? Is this quantity of work o

btainable in practice? Explain.
Chemistry
1 answer:
nevsk [136]11 months ago
7 0

Free energy is used to determine how systems change and how much work they can produce.

If the free energy of the reactants is greater than that of the products, the entropy  will increase when the reaction takes place  so the reaction will tend to take place spontaneously. If the free energy of the products exceeds that of the reactants, then the reaction will not take place

The Gibb's free energy change (ΔG) is:

ΔG<0⟶ Spontaneous process

ΔG>0⟶  Non-spontaneous process

ΔG=0⟶ Equilibrium process or reversible process

Gibb's free energy is a quantity used to measure the maximum amount of work done in a thermodynamic system , when the temperature and pressure are constant .

It is a state function hence it doesn't depend on path .

ΔG = ΔH - T(ΔS)

Learn more about free energy here :

brainly.com/question/10012881

#SPJ4

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Please help I will mark Brainly!
olga nikolaevna [1]
I think C. Ionic compounds are very difficult to break apart because they are fully negative or positive charges, like magnets.
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3 years ago
Write the combustion product of butane in excess<br> oxygen.
Leto [7]

Answer:

The name of the products are CO2 = carbon dioxide and H2O = water. The type of reaction is a combustion reaction.

Explanation:

8 0
3 years ago
Read 2 more answers
What is the Molar mass of PbCO4
NNADVOKAT [17]

Answer:

207.2 g/mol

Explanation:

Hopes help

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3 years ago
A covalent chemical bond is one in which
vitfil [10]
I think the answer is c
4 0
3 years ago
Complete combustion of a 17.12mg sample of xylene In oxygen yielded 56.77mg
Veronika [31]

Xylene moles =\frac{17.12}{106.16×1000}=0.00016moles=

106.16×1000

17.12

=0.00016moles

Moles of CO_2 =\frac{56.77}{44.01×1000}=0.0013CO

2

=

44.01×1000

56.77

=0.0013

Moles of H_2O= =\frac{14.53}{18.02×1000}=0.0008H

2

O==

18.02×1000

14.53

=0.0008

Moles ratios

\frac{0.0013}{0.0008}=1.625

0.0008

0.0013

=1.625

\frac{0.0008}{0.0008}=1

0.0008

0.0008

=1

Hence molecular fomula

The empirical formula is C 4H 5.

The molecular formula C8H10

8 0
2 years ago
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