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abruzzese [7]
1 year ago
9

McLin, Inc. is a calendar year S corporation. Its accumulated adjustments account (AAA) balance is zero.

Engineering
1 answer:
musickatia [10]1 year ago
3 0

Total Tax could be saved by the S Corporation and Ruby is $6,120.

How can we save tax ?

1) Calculating the tax implications if Tobias receives a $90,000 salary:

The Tobias acknowledge the $90,000 in ordinary income. Tobias receives a $90,000 deduction from the Corporation. His stock basis is thus decreased to $0 as a result. He then has a $10,000 Loss Carryover.

Similar to part (a), but McLin gives Tobias a $90,000 dividend from AEP instead:

The Tobias family recognizes the $90,000 in dividend income. Pass-through without deductions; $80,000 in remaining stock basis. The AEP is then decreased to $0.

2) The Strauder's Ending OAA balance is calculated as follows:

Beginning Balance of OAA$5,200

Tax-exempt interest income$4,995

Life insurance premiums paid (nondeductible)($3,333)

Nontaxable life insurance proceeds$50,000

Ending Balance of OAA$57,362

Therefore, the Strauder's Ending OAA balance is $57,362.

3)Calculation of the Stock Bases of Each Shareholder at the End of the Year:

AndreCrumBarbaraBeginning basis$12,000$22,000$28,000

Add: Short Term Capital Gain ($37,500/3)$12,500$12,500$12,500

Nondeductible fees and penalties ($3,000/3)($1,000)($1,000)($1,000)

Long-term capital loss ($6,000/3)($2,000)($2,000)($2,000)

Net tax operating loss ($30,000/3)($10,000)($10,000)($10,000)

Less: Distribution, cash($6,000)($6,000)($6,000)

Ending Stock Basis$5,500$15,500$21,5004)

Calculation of the Total Tax could be Saved.

Ruby and the S Corporation can each save $3,060 in FICA taxes, for a total savings of $6,120:

Therefore, the Total Tax could be saved by the S Corporation and Ruby is $6,120.

To know more about Tax, check out:

brainly.com/question/16423331

#SPJ4

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Refrigerant-134a enters the expansion valve of a refrigeration system at 120 psia as a saturated liquid and leaves at 20 psia. D
Shkiper50 [21]

Solution :

$P_1 = 120 \ psia$

$P_2 = 20 \ psia$

Using the data table for refrigerant-134a at P = 120 psia

$h_1=h_f=40.8365 \ Btu/lbm$

$u_1=u_f=40.5485 \ Btu/lbm$

$T_{sat}=87.745^\circ  F$

∴ $h_2=h_1=40.8365 \ Btu/lbm$

For pressure, P = 20 psia

$h_{2f} = 11.445 \ Btu/lbm$

$h_{2g} = 102.73 \ Btu/lbm$

$u_{2f} = 11.401 \ Btu/lbm$

$u_{2g} = 94.3 \ Btu/lbm$

$T_2=T_{sat}=-2.43^\circ  F$

Change in temperature, $\Delta T = T_2-T_1$

                                         $\Delta T = -2.43-87.745$

                                           $\Delta T=-90.175^\circ  F$

Now we find the quality,

$h_2=h_f+x_2(h_g-h_f)$

$40.8365=11.445+x_2(91.282)$

$x_2=0.32198$

The final energy,

$u_2=u_f+x_2.u_{fg}$

   $=11.401+0.32198(82.898)$

   $=38.09297 \ Btu/lbm$

Change in internal energy  

$\Delta u= u_2-u_1$

   = 38.09297-40.5485

  = -2.4556        

5 0
2 years ago
Which statement about tensile stress is true? A. Forces that act perpendicular to the surface and pull an object apart exert a t
svp [43]

Answer:

A. Forces that act perpendicular to the surface and pull an object apart exert a tensile stress on the object.

Explanation:

Tensile stress is referred as a deforming force, in which force acts perpendicular to the surface and pull an object apart, attempting to elongate it.

The tensile stress is a type of normal stress, in which a perpendicular force creates the stress to an object’s surface.

Hence, the correct option is "A."

3 0
3 years ago
The diagram illustrates a method of producing plastics called​
hodyreva [135]

Answer:

polymerisation,

Explanation:

6 0
2 years ago
Describe the greatest power in design according to Aravena?
Ann [662]

Answer: Describe the greatest power in design according to Aravena? The subject of Aravena’s recent Futuna Lecture Series in New Zealand was ‘the power of design,’ which he described as ultimately being “the power of synthesis” because, increasingly, architects are dealing with complex issues and problems.

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4 0
2 years ago
A closed system consists of 0.3 kmol of octane occupying a volume of 5 m³. Determine (a) the weight of the system, in N, and (b)
Leni [432]

Answer:

a) m=336.18N

b) Vn=16.67m/kmol

Vm=0.1459m^3/kg

Explanation:

To calculate the mass of the octane(m):

Number of mole of octane (n) =0.3kmol(given)

Molarmass of octane (M) =114.23kg/kmol

m=n*M

m=(0.3kmol)*(114.23kg/kmol)

m=34.269kg

To calculate for the weight of octane(W):

W=g*m

W=(9.81m/s^2)*(34.269kg)

W=336.18N

b) For specific volumes of Vn and Vm:

Given volume of octane (V) =5m^3

Vm=V/m

Vm=5m^3/34.269kg

Vm=0.1459m^3/kg

And Vn will be :

Vn=V/m=5m^3/0.3kmol

Vn=16.67m/Kmol

Therefore, the answers are:

a) m=336.18N

b) Vn=16.67m/kmol

Vm=0.1459m^3/kg

7 0
3 years ago
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