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BARSIC [14]
1 year ago
8

A mass m is attached to an ideal massless spring with spring constant k. In experiment 1 the mass oscillates with amplitude a, a

nd period t. A student grabs the mass and brings it to rest before starting experiment 2. In experiment 2, the mass is set to oscillate with a larger amplitude of 3a. What is the period of the oscillation in experiment 2?.
Physics
1 answer:
JulijaS [17]1 year ago
6 0

The experiment's time period is unaffected by the change in amplitude in either experiment.

<h3>What are the variables that affect time in SHM?</h3>

The time frame is provided by:

$T=2 \pi \sqrt{\frac{m}{k}}$

where,

T = Time period.

M = mass.

k = spring constant.

We can see from the formula above that the only factors affecting the time period in a Simple Harmonic Motion (SHM) are the object's mass and spring constant. Any changes in the object's mass or the spring constant will cause the time period to adapt.

<h3>Describe the Spring Constant.</h3>

The attribute is known as a spring's "spring constant" describes the relationship between the force acting on a spring and the displacement it causes. In other terms, it describes the stiffness and size of a spring's range of motion.

To know more about Simple Harmonic Motion (SHM) visit:

brainly.com/question/17315536

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Which invention was created to help people with hearing problems? the multiplex telegraph the telephone the phonograph the motio
Nataliya [291]

The phonograph was invented for people with hearing problems. Option D is correct.

<h3>What is a Phonograph?</h3>
  • It is a device that records sounds or music in the grooves of a plate and plays them.
  • This was the first invention that can record and play music.
  • It was invented by Thomas Alva Edison.
  • This device helps people with hearing problems by allowing them to practice concentrating on a different sound.

Therefore, the phonograph was invented for people with hearing problems.

Learn more about Phonograph:

brainly.com/question/858851

7 0
3 years ago
The tendency of an object to resist a change in its motion
Olenka [21]

Answer:

Inertia Newtons First law

Explanation:

 

3 0
3 years ago
A 1000kg roller coaster begins at 10m tall hill with initial velocity of 6m/s and travels down until a second hill. 1700J is tra
nadezda [96]

Answer:

The maximum height could be 10.6 meters.

Explanation:

For this kind of exercise, we use the general principle for conservation of mechanical energy (E) that states:

E_1+W_f=E_2 (1)

That means the mechanical energy an object has on a point 2 should be equal to the mechanical energy on a point 1 plus the energy transformed into heat due friction denoted as Wf (It is negative because is lost). In our case point 1 is the point where the roller coaster begins and point 2 is at the second hill. Tola mechanical energy is the sum of potential gravitational energy and kinetic energy, so (1) is :

K_{1}+U_{1}+W_{f}=K_{2}+U_{2}

with K the kinetic energy and U the potential energy, remember potential energy is mgh and kinetic energy is \frac{mv^2}{2} with m the mass, v the velocity and h the height, then:

\frac{mv_1^2}{2}+mgh_1+W_{f}=\frac{mv_2^2}{2}+mgh_2

Solving for h_2:

h_2=\frac{\frac{mv_1^2}{2}+mgh_1+W_{f}-\frac{mv_2^2}{2}}{mg}=\frac{\frac{(1000)(6)^2}{2}+(1000)(9.8)(10)-1700-\frac{(1000)(4.6)^2}{2}}{(1000)(9.81)}

h_2=10.6 m

4 0
4 years ago
A 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving
julia-pushkina [17]

Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.

<h3>Conservation of Linear Momentum</h3>

It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.

Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.

The given parameters are;

  • M1 = 7500 kg
  • U1 = 5 m/s
  • M2 = 1500
  • U2 = 20 sin 30 = 10 m/s
  • V = ?

The formula to find the speed will be

M1U1 - M2U2 = (M1 + M2)V

7500 × 5 - 1500 × 10 = (7500 + 1500)V

37500 - 15000 = 9000V

22500 = 9000V

V = 22500/9000

V = 2.5 m/s

Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.

Learn more about Collision here: brainly.com/question/7694106

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5 0
1 year ago
A boy throws a ball straight up into the air. It reaches the highest point of its flight after 4 seconds.
Zanzabum

Answer:Take into account the the Earths gravity is 9.8 meters a second

Explanation:

Gravity pulls down on the ball at g=-9.81 m/s^2. Up is positive, down is negative.The ball started at a certain initial velocity of Vi m/s. Time it took is t=4s. Final velocity is Vf=0 m/s, because at the highest point the ball stops moving.

Vf=(g*t)+Vi

Rearrange for Vi.

Vi=Vf-(g*t)

Vi=0-(-9.81*4)=39.24 m/s (upward)

Think about it this way for the non-mathematical approach. The ball stops at the top. The initial velocity gets reduced by 9.81 m/s every second, and reaches 0 m/s at the top. It took 4 seconds, so 9.81*4 is equal to the initial upward velocity.

8 0
3 years ago
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