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BARSIC [14]
1 year ago
8

A mass m is attached to an ideal massless spring with spring constant k. In experiment 1 the mass oscillates with amplitude a, a

nd period t. A student grabs the mass and brings it to rest before starting experiment 2. In experiment 2, the mass is set to oscillate with a larger amplitude of 3a. What is the period of the oscillation in experiment 2?.
Physics
1 answer:
JulijaS [17]1 year ago
6 0

The experiment's time period is unaffected by the change in amplitude in either experiment.

<h3>What are the variables that affect time in SHM?</h3>

The time frame is provided by:

$T=2 \pi \sqrt{\frac{m}{k}}$

where,

T = Time period.

M = mass.

k = spring constant.

We can see from the formula above that the only factors affecting the time period in a Simple Harmonic Motion (SHM) are the object's mass and spring constant. Any changes in the object's mass or the spring constant will cause the time period to adapt.

<h3>Describe the Spring Constant.</h3>

The attribute is known as a spring's "spring constant" describes the relationship between the force acting on a spring and the displacement it causes. In other terms, it describes the stiffness and size of a spring's range of motion.

To know more about Simple Harmonic Motion (SHM) visit:

brainly.com/question/17315536

#SPJ4

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