Question

What is the decibel level of a whisper with intensity 10^−10 watts per square inch?

Answer 1

The intensity of sound in the unit of decibel is, 1.90*10^-5W/m^2.

To find the answer, we have to know about the intensity of sound.

How to find the intensity of sound in decibel?

• The rate of transfer of energy per unit area perpendicular to the direction of propagation of sound is called the intensity of sound.
• We have the expression for intensity of sound in the unit of decibel as,

                                   $I_{dB}=10 log(\frac{I}{I_0} )$

• It is given that, the intensity of whisper with intensity 10^−10 watts per square inch, and the threshold value of intensity is,

                  $I_0=10^{-2}W/m^2\\I=10^{-10}W/inch^2=10^{-10}W/(0.0254)^2m^2=1.55*10^{-7}$

• Thus, in dB the intensity is,

                 $I_{dB}=10log(\frac{1.55*10^{-7}}{10^{-2}} )=1.90*10^{-5}W/m^2$

Thus, we can conclude that, the intensity of sound in the unit of decibel is, 1.90*10^-5W/m^2.

Learn more about the intensity of sound here:

brainly.com/question/15866608

#SPJ4