Question

The transmutation of a radioactive uranium isotope, 234/92 U, into a radon isotope, 222/86 Rn, involves a series of three nuclear reactions. At the end of the first reaction, a thorium isotope, 230/90 Th, is formed and at the end of the second reaction, a radium isotope, 226/88 Ra, is formed. In both the reactions, an alpha particle is emitted. Write the balanced equations for the three successive nuclear reactions. Please show all work.

Answer 1

Answer : The balanced equations for the three successive nuclear reactions are:

First reaction will be:                

$_{92}^{234}\textrm{U}\rightarrow _{90}^{230}Th+_2^4He$

Second reaction will be:                  

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}Ra+_2^4He$

Third reaction will be:                    

$_{88}^{226}\textrm{Ra}\rightarrow _{86}^{222}Rn+_2^4He$

Explanation :

Alpha decay : In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

The general representation of alpha decay reaction is:

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha$

The balanced equations for the three successive nuclear reactions are:

First reaction will be:                

$_{92}^{234}\textrm{U}\rightarrow _{90}^{230}Th+_2^4He$

Second reaction will be:                  

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}Ra+_2^4He$

Third reaction will be:                    

$_{88}^{226}\textrm{Ra}\rightarrow _{86}^{222}Rn+_2^4He$

Answer 2

Answer:

The answer is 26/98 how i did this is i divided them mulitiplyed well i cant really explain it but im pretty dure its right

Explanation: