Answer:
v = 5.38 m/s
Explanation:
Given that,
A tennis ball is dropped from 1.48 m above the ground, d = 1.48 m
It rebounds to a height of 0.956 m
We need to find the velocity of the ball when it hits the ground. Using equation of kinematics as follows :
So, when the ball hits the ground, its velocity is 5.38 m/s.
Thermal- transfer of heat thru space
Radiation- the average amount of energy of motion in the molecules of a substance
Thermometer- a thin glass tube with a bulb on one end that contains a liquid, usually mercury or colored alcohol
Brainly?
Answer:
Explanation:
Let the velocity of projectile be v and angle of throw be θ.
The projectile takes 5 s to touch the ground during which period it falls vertically by 100 m
considering its vertical displacement
h = - ut +1/2 g t²
100 = - vsinθ x 5 + .5 x 9.8 x 5²
5vsinθ = 222.5
vsinθ = 44.5
It covers 160 horizontally in 5 s
vcosθ x 5 = 160
v cosθ = 32
squaring and adding
v²sin²θ +v² cos²θ = 44.4² + 32²
v² = 1971.36 + 1024
v = 54.73 m /s
Answer: false
Explanation: friction makes objects slow down and stop
A cold front phenomenon characterized by cold air pushing into much warmer air mass. The cold air being more dense than warm air is able to effectively push it forward usually at a fast pace.
When the cold front is passing through an area, there are gusts of wind which usually sweep right across the ground and raise the dust in dry areas, there is a sudden drop in temperature with moderate to heavy rain sometimes with thunder, lightning and hail.
The warm air moving ahead of the cold front produces cumulus or cumulonimbus clouds with thunderstorms as atmospheric pressure falls then slowly rises again after the cold front has passed.
Temperatures are noticeably cooler in a given area after a cold front has passed, which is followed by replacement of cumulus clouds by stratus and stratocumulus clouds and clear skies.