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3 years ago

How do you find the average atomic mass

Chemistry

1 answer:

nekit [7.7K]3 years ago

8 0

Answer:

To calculate the average atomic mass, multiply the fraction by the mass number for each isotope, then add them together.

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How do cherries in a cherry tree help the plant reproduce

Harlamova29_29 [7]

Because if the cherries are eaten them the seeds/pit will be eaten as well which will be carried by whatever ate it and pooped out and can make more of its kind but it is different with wind and water do you also want that answer?

7 0

3 years ago

Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o

vivado [14]

Answer:

For 1: The amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2: The amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

Explanation:

For 1:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of $KIO_3$ solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

$0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol$

Hence, the amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2:

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

$2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3$

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = $\frac{1}{2}\times 0.00025=0.000125mol$ of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

6 0

3 years ago

What is a graph?

Keith_Richards [23]

*Visual

*Independent

*Dependent

5 0

3 years ago

The electron configuration for aluminum (Al) is shown below:

Serjik [45]

Answer:

It is the third choice

Explanation:

Just did assignment

3 0

4 years ago

In a strong acid–strong base titration (both monoprotic), if 25.0 milliliters of the base is required to completely neutralize 2

taurus [48]

B)The concentration of the acid (C₁) is the same as that of the base (C₂).

V₁=V₂

n(acid)=C₁V₁
n(base)=C₂V₂

HX + YOH = YX + H₂O

n(acid)=n(base)

C₁V₁=C₂V₂

C₁=C₂

5 0

3 years ago

Read 2 more answers