Answer: The child isotope has an atomic mass of 206.
Explanation:
Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.
General representation of an element is given as: 
where,
Z represents Atomic number
A represents Mass number
X represents the symbol of an element
General representation of alpha decay :
Answer:
The formation of large molecules from small repeating units is known as <u>Condensation</u> reactions.
Explanation:
Those reactions in which two molecules join together with a elimination of small neutral molecule like H₂O, CH₃OH, HCl e.t.c are known as condensation reactions.
Polymerization reactions are those reactions in which small molecules called as monomers join together to form a large molecule also known as polymers. These reactions are done via different mechanisms among which one is the condensation reaction.
Example:
Proteins (polymer) are made up of amino acids (monomers) through condensation reaction as,
n H₂N-RH-COOH → H₂N-[-RH]n-COOH + n H₂O
In above equation "n" represent large number, H₂N-RH-COOH represent amino acid (monomer) and H₂N-[-RH]n-COOH represent protein (polymer). While, the H₂O eliminated is the small neutral molecule.
Answer:
Volume of HNO₃ required = 140 mL
Explanation:
Given data:
Molarity of HNO₃ = 0.563 M
mass of BaCO₃ = 7.83 g
Volume of HNO₃ = ?
Solution:
First of all we will write the balance chemical equation
2HNO₃ + BaCO₃ → Ba(NO₃)₂ + H₂O + CO₂
Number of moles of BaCO₃ = mass / molar mass
Number of moles of BaCO₃ = 7.83 g / 197.34 g/mol
Number of moles of BaCO₃ = 0.04 mol
Now we compare the moles of BaCO₃ and HNO₃ .
BaCO₃ : HNO₃
1 : 2
0.04 : 2×0.04 = 0.08 mol
Volume of HNO₃ required = number of moles / Molarity
Volume of HNO₃ required = 0.08 mol / 0.563 mol/L
Volume of HNO₃ required = 0.14 L
0.14 × 1000 = 140 mL
Answer:
403 mL
Explanation:
First, I will assume that the mole is 1, because you are not specifing this.
Now, with the innitial data, we need to get the pressure:
T = 65+273 = 338 K
V = 500 / 1000 = 0.5 L
Now if:
PV = nRT
Then:
P = nRT/V and V = nRT/P
Let's calculate the P:
P = 1 * 0.082 * 338 / 0.5 = 55.432 atm
The standard temperature is 0° C or 273 K so, the volume is:
V = 1 * 0.082 * 273 / 55.432
V = 0.40384 L or simply 403.84 mL
