Answer:
The ion has fewer electrons
Explanation:
As Rubidium forms a positive ion Rb⁺ the number of electrons becomes fewer for the atom.
- A positive charge on an ion indicates that the number of protons for the atom is greater than the number of electrons.
- This leaves a net positive charge on the atom.
- For a negatively charged ion, the number of electrons is more than the number of protons because they have gained additional electrons.
- In a neutral atom, the number of protons and electrons are the same.
Answer:
1.6s
Explanation:
Given that A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction,
To know how fast the ball will roll when it reaches the bottom of the incline, we need to calculate the acceleration at which it is rolling.
Since the frictional force is negligible, at the top of the incline plane, the potential energy = mgh
Where h = 5.2sin25
h = 2.2 m
P.E = 1.2 × 9.8 × 2.2
P.E = 25.84 j
At the bottom, K.E = P.E
1/2mv^2 = 25.84
Substitutes mass into the formula
1.2 × V^2 = 51.69
V^2 = 51.69/1.2
V^2 = 43.07
V = 6.56 m/s
Using the third equation of motion
V^2 = U^2 + 2as
Since the object started from rest,
U = 0
6.56^2 = 2 × a × 5.2
43.07 = 10.4a
a = 43.07/10.4
a = 4.14 m/s^2
Using the first equation of motion,
V = U + at
Where U = 0
6.56 = 4.14t
t = 6.56/4.14
t = 1.58s
Therefore, the time the ball rolls when it reaches the bottom of the incline is approximately 1.6s
Answer:
(a) the particle position = 135 m
(b) the velocity of the particle = 44 m/s
(c) the acceleration of the particle = 50 m/s²
Explanation:
Solution to Question 2.
Given;
velocity of a particle, v = 2 - 4t + 2t³
initial position at t = 0, s₀ = 3 m
(a) the particle position at t = 3 s
s = vt
s = (2 - 4t + 2t³)t
s = 2t - 4t² + 2t⁴
s = s₀ + s₃
s = s₀ + 2(3) - 4(3²) + 2(3⁴)
s = s₀ + 6 - 36 + 162
s = s₀ + 132 m
s = 3m + 132 m
s = 135 m
(b) the velocity of the particle at t = 3 s
v = 2 - 4t + 2t³ = 2 - 4(3) + 2(3)³
v = 44 m/s
(c) the acceleration of the particle at t = 3s
v = 2 - 4t + 2t³
a = -4 + 6(3)²
a = 50 m/s²
The answer is:
noble gases will not form compounds.
The explanation:
-The noble gas family, all of the elements in Group Zero.
-The list of noble gases include helium(He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn).
- these elements don't like to react, we don't use them because of they have 8 valence electrons already and don't like to lose or gain electrons so, they will not form compounds.
<span>It is a vector quantity because it involves magnitude and direction.</span>
