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GenaCL600 [577]
2 years ago
13

For a first-order reaction, after 2.00 min, 20% of the reactants remain. Calculate the rate constant for the reaction. 1. 74.6 s

−1 2. 0.00582 s−1 3. 0.000808 s−1 4. 0.00186 s−1 5. 0.013412 s−1
Chemistry
1 answer:
garri49 [273]2 years ago
7 0

<u>Answer:</u> The rate constant for the reaction is 0.013412s^{-1}

<u>Explanation:</u>

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = ?

t = time taken for decay process = 2.00 min = 120 seconds   (Conversion factor: 1 min = 60 seconds)

[A_o] = initial amount of the sample = 100 grams

[A] = amount left after decay process =  20 grams

Putting values in above equation, we get:

k=\frac{2.303}{120}\log\frac{100}{20}\\\\k=0.013412s^{-1}

Hence, the rate constant for the reaction is 0.013412s^{-1}

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