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Snowcat [4.5K]
3 years ago
14

In the heat equation what does Q represent

Physics
2 answers:
Burka [1]3 years ago
6 0
Q stands for heat energy (Joules) hope this helps!
svlad2 [7]3 years ago
3 0

A. heat required to raise the temperature

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a sensor light installed on the edge of a home can detect motion for a distance of 50 feet in front and with a range of motion o
Dvinal [7]

Answer:

4363.3231 feets²

Explanation:

Given that :

Distance, r = 50 ft

θ = 200°

The arc length of area covered :

Arc length = θ/360° * πr²

Arc length = (200/360) * 50 ft ^2 * π

Arc length = 0.5555555 * 2500 * π

Arc length = 4363.3231 feets²

7 0
3 years ago
Science: Please help me with this due in 5 minutes
babunello [35]

Answer: Use less water

only turn on lights when needed

electrical cars

less gas usage

Explanation:

6 0
3 years ago
Can a body have constant speed and still be acclerating ? Give an Example
Allushta [10]






Hi Pupil Here's Your answer :::





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An object moving with constant speed can be accelerated if direction of motion changes. For example, an object moving with a constant speed in a circular path has an acceleration because its direction of motion changes continuously.





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Hope this Helps . . . . . . . . .
3 0
4 years ago
Each value in nature has a number part, called its____<br> and a dimension, or unit
saul85 [17]

Answer:

<u>Magnitude</u>

Explanation:

Each value in nature has a number part, called its magnitude and a dimension called its unit.

For example,

The length of an object is 10 cm. It means that 10 shows the magnitude of length and cm shows its unit.

7 0
3 years ago
Help me please I can't get the final step​
inna [77]

Answer:

\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}

Explanation:

<u>Dimensional Analysis</u>

It's given the relation between quantities A, B, and C as follows:

\displaystyle A=\frac{3}{2}B^mC^n

and the dimensions of each variable is:

A=L^2T^2

B=LT^{-1}

C=LT^2

Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n

Operating:

L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)

L^2T^2=L^{m+m}T^{-m+2n}

Equating the exponents:

m+n=2

-m+2n=2

Adding both equations:

3n=4

Solving:

n=4/3

m=2-4/3=2/3

Answer:

\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}

6 0
3 years ago
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