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Alekssandra [29.7K]
3 years ago
11

Suppose that you want to test the effects of different dishwashing detergents on dishes that have food stuck to them. To test th

e differences, you wash three loads of the same dishes, each with a different type of detergent, all in warm water. You also wash a fourth load of dishes with only warm water. The independent variable in this experiment is the type of detergent used. true or false?
Chemistry
1 answer:
valentina_108 [34]3 years ago
8 0
Yes, it is very much true. The type of detergent (or independent variable) affects how clean the dishes will be (dependent variable). Hope this helps, if you have anymore questions, feel free to ask!
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Someone please ASAP<br> the options are <br> 1. BF.<br> 2.B4<br> 3.B2F2<br> 3.BF3
arlik [135]

Answer:

B4

Explanation:

good day

6 0
2 years ago
5.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 7
slega [8]

Answer:

The molecular formula = C6H6

Explanation:

Step 1: Data given

Mass of compound X = 5.00 grams

Mass of products =

  CO2 = 16.39 grams

  H2O = 3.46 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16. 0g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles CO2 = 16.93 grams / 44.01 g/mol

Moles CO2 =  0.385 moles

Moles C = 1* 0.385 = 0.385 moles

Moles H2O = 3.46 grams / 18.02

Moles H2O = 0.192 moles

Moles H = 2* 0.192 = 0.384 moles

Step 3: Calculate mass

Mass = moles * molar mass

Mass C = 0.385 moles *12.0 g/mol

Mass C = 4.62 grams

Mass H = 0.39 grams

Mass O = 5.00 - 4.62 -0.38 moles

Mass O = 0 grams

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.385 moles / 0.384 = 1

H: 0.384 moles / 0.384 = 1

The empirical formula is CH

This molecular formula is 13 g/mol

We have to multiply the empirical formula by n

n = 78 g/mol / 13 g/mol

n = 6

The molecular formula = 6*(CH) = C6H6

4 0
3 years ago
1) You are asked to make 10 miles of iron (Fe) from iron oxide (Fe2O3) and excess carbon monoxide (CO). Fe2O3(s) + 3CO(g)—&gt; 2
Inessa05 [86]

For both of them, used the balanced equation and it’s mole ratio to convert whatever you need to into moles. See the attacked work.

1) D 5 mols

2) A 0.55 mols

8 0
3 years ago
What volume will 12.0 g of oxygen gas occupy at 25 c and a pressure of 52.7 kpa?
Stolb23 [73]
We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume 
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation 
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
 V = 17.6 L
volume of the gas is 17.6 L
8 0
3 years ago
does the nitro group on the pyridine ring make the ring more electron rich or more electron deficient
Arte-miy333 [17]

Answer:

more electron deficient

Explanation:

The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.

This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.

Hence, the nitro group makes the pyrinde ring more electron deficient

3 0
2 years ago
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