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MariettaO [177]
4 years ago
8

Solid solution strengthening is achieved byGroup of answer choicesstrain hardening restricting the dislocation motion increasing

the dislocation motion increasing the grain boundary g
Engineering
1 answer:
enot [183]4 years ago
4 0

Answer:

B. restricting the dislocation motion

Explanation:

Solid solution strengthening is a type of alloying that is carried out by the addition of the atoms of the element used for the alloying to the crystallized lattice structure of the base metal, which the metal that would be strengthened. The purpose of this act is to increase the strength of metals. It actually works by impeding or restricting the motion in the crystal lattice structure of metals thus making them more difficult to deform.

The solute atoms used for strengthening could be interstitial or substitutional. The interstitial solute atoms work by moving in between the space in the atoms of the base metal while the substitutional solute atoms make a replacement with the solvent atoms in the base metal.

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A 900 kg car is accelerated from a speed of 10 m/s to 30 m/s. An estimated heat loss of 20 BTU's occurs during the acceleration.
Strike441 [17]

Answer:

Work = 651,1011 kJ

Explanation:

Let´s take the car as a system in order to apply the first law of thermodynamics as follows:

E_{in}- E_{out}=E_{system,final}- E_{system,initial}

Where

E_{in}- E_{out}=(Q_{in}-Q_{out})_{heat}+(W_{in}-W_{out})_{work}+(Em_{in}-Em_{out})_{mass}

And considering that there is no mass transfer and that the only energy flows that interact with the system are the heat losses and the work needed to move the car we have:

E_{in}- E_{out}=-Q_{out}+W_{in}

Regarding the energy system we have the following:

E_{system,final}- E_{system,initial}=(U_{f}-U_{i})_{internal}+(1/2m(V^2_{f}-V^2_{i}))_{kinetic}+(mg(h_{f}-h_{i}))_{potential}

By doing the calculations we have:

E_{system,final}- E_{system,initial}=[0,1*900]_{internal}+[0,5*900(30^2-10^2)/1000)_{kinetic}+(900*10*(20-0)/1000)_{potential}\\E_{system,final}- E_{system,initial}=90+360+180=630kJ

Consider that in the previous calculation, the kinetic and potential energy terms were divided by 1.000 to change the units from J to kJ.

Finally, the work needed to move the car under the required conditions is calculated as follows:

W_{in}=Q_{out}+E_{system,final}- E_{system,initial}\\W_{in}=21,1011+630=651,1011kJ

Consider that in the previous calculation, the heat loss was changed previously from BTU to kJ.

4 0
3 years ago
Consider the database table structure shown in the figure. (a) Write a SELECT statement statement (compatible with an Oracle RDB
Delicious77 [7]

Answer:

The table is attached as a picture.

a)

Select VENDOR_CONTACT_LAST_NAME || ', ' || VENDOR_CONTACT_FIRST_NAME "full_name" from VENDORS where VENDOR_CONTACT_LAST_NAME like 'A%' or VENDOR_CONTACT_LAST_NAME like 'E%' order by VENDOR_CONTACT_LAST_NAME,VENDOR_CONTACT_FIRST_NAME;

concatenation operator || is used . Also LIKE is used for pattern matching. full_name is alias for the concatenated column

b) As sample data is not given ,Please test the query for the data given in table

Explanation:

6 0
3 years ago
What chemicals go into lake michigan
solniwko [45]

Answer:

They include PCBs, dioxins, furans, hexachlorobenzene, benzo(a)pyrene (one of many polyaromatic hydrocarbons or PAHs), lead and mercury compounds and pesticides (toxaphene, mirex, aldrin/dieldrin, DDT). 3 Great Lakes Water Quality Agreement Work Group Report on Chemicals of Emerging Concern, August 2009.

7 0
4 years ago
Read 2 more answers
First drilled to a depth of 1 47/64 how much deeper must it be drilled to reach the depth indicated?
lara [203]

Answer:

  1 13/64

Explanation:

The depth of the hole is the height of the block less the remaining material below the hole:

  depth = 1 3/8 +1 15/16 - 3/8 = (1 3/8 -3/8) +1 15/16 = 2 15/16

We want to find the difference between this depth and the depth of the hole already drilled:

  2 15/16 -1 47/64 = 2 60/64 -1 47/64

  = (2 -1) +(60 -47)/64 = 1 13/64

The hole must be drilled 1 13/64 deeper to match the drawing.

7 0
2 years ago
The amplitudes of the displacement and acceleration of an unbalanced motor were measured to be 0.15 mm and 0.6 g, respectively.
PilotLPTM [1.2K]

Answer:

N=945.76 RPM

Explanation:

Given that

A= 0.15 m

Acceleration = 0.6 g

a=0.6 x 9.81 m/s²

a= 5.886 m/s²

We know that acceleration a given as

a = ω² A

ω=Angular speed

\omega=\sqrt{\dfrac{0.6\times 9.81}{0.6\times 10^{-3}}}

 ω=99.04 rad/s

We know that

\omega=\dfrac{2\pi N}{60}\\\\N=\dfrac{60\times \omega}{2\pi }

N=\dfrac{60\times 99.04}{2\pi }

N=945.76 RPM

Therefore the speed of the motor will be 945.76 RPM.

6 0
4 years ago
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