Question

Scenario

Answer 1

Answer: The element having number of protons 120 will belong to Group 2, Period 8 and has an atomic number of 120.

Explanation:

We are given:

Number of protons = 120

Atomic number is equal to the number of protons present in neutral atom.

Atomic number of element = 120

Electronic configuration of element: $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^{14}5d^{10}6p^67s^25f^{14}6d^{10}7p^68s^2$

Electronic configuration of element in terms of noble gas: $[Og]8s^2$

As, the last electron is entering in s-orbital. So, it is an s-block element and there are 2 electrons in the outermost shell. So, it will belong to Group-2.

And, the value of Principal Quantum number (n) for this element is '8'. Therefor, it will belong to Period 8.

Hence, the element having number of protons 120 will belong to Group 2, Period 8 and has an atomic number of 120.