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lesya [120]
3 years ago
15

According to the work-energy theorem, the amount of work done can be determined using which formula?

Physics
1 answer:
torisob [31]3 years ago
6 0

Answer:

W=\Delta KE= KE_f-KE_i=\frac{1}{2} \,m \,v_f^2-\frac{1}{2} \,m \,v_i^2

Explanation:

The Work-Kinetic Energy Theorem states that the work done on a particle of mass "m", equals the particle's change in Kinetic Energy (final Kinetic Energy of the particle "KE_f" minus the initial Kinetic energy of the particle "KE_i"), and it is expressed as:

W=\Delta KE= KE_f-KE_i=\frac{1}{2} \,m \,v_f^2-\frac{1}{2} \,m \,v_i^2

where we have used the explicit form of the KE of a particle of mass m and velocity v. Of course, v_f stands for the final velocity of the particle, and v_i for the particle's initial velocity.

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Answer:

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Explanation:

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3 years ago
Calculate the number of free electrons and holes (in m-3) in an intrinsic semiconductor that has electron and hole mobilities of
allochka39001 [22]

Answer:

ni = 2.04e19

Explanation:

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\sigma = ni\left | e \right | \mu_e  + ni\left | e \right | \mu_h

\sigma = ni \left | e \right | ( \mu_e + \mu_h)

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An electromagnet is a solenoid with a piece of ferromagnetic material within it.
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