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4 years ago

As the arm lifts the mass, does elbow angle increase or decrease?

Physics

1 answer:

Semenov [28]4 years ago

6 0

In increases depends how you move the muscle

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What is the largest area of specialization in psychology

Sindrei [870]

Answer:clinical psychology

Explanation:

The largest area of specialization in psychology is clinical psychology

5 0

3 years ago

An astronaut in a satellite 1600km above the Earth experience a gravitational force magnitude 700N on earth.The Earth's radius i

Brilliant_brown [7]

Answer:

The magnitude of the gravitational force which the astronaut experience in satellite $= 448$ Newton

Explanation:

As we know

Gravitational force F = $\frac{GMm}{r^2}$

Where G is the gravitational constant $6.67 * 10^{-11}$

M is the mass of earth $= 6* 10^{24}$

m is not given

r is the radius of earth $6 400*10^3$

Substituting the given values, we get -

$F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3)^2}$

$m = 71.6$ Kg

Gravitational force in the satellite

$F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3 + 1600 *10^3)^2}\\F = 448$ N

3 0

3 years ago

What does it mean to say that the average speed of a car is 35 miles per hour?

LenKa [72]

It means that the car has covered

(35 miles) x (the number of hours since it started traveling).

At some points during that time, the car was most likely moving
faster or slower than 35 miles per hour. We don't know. We only
know that it covered (35 miles) x (the number of hours since it left).

6 0

3 years ago

Which describes increasing the efficiancy of an energy resource?

RUDIKE [14]

making cars that get better gas mileage

4 0

4 years ago

Two people carry a heavy electric motor by placing it on a light board 1.50 m long. One person lifts at one end with a force of

ankoles [38]

Answer:

a) The weight of the motor is 1120 N

b) The distance of the center of gravity is 1.71 m

c) The weight of the motor is 920 N

d) The distance of the center of gravity is 1.79 m

Explanation:

a) The expression of the forces acting in the vertical direction is:

wmotor = F1 + F2

F1 = 410 N

F2 = 710 N

wmotor = 410 + 710 = 1120 N

b) The momentum of equilibrium about the center of the gravity is:

F1 * x = F2 * (l - x)

Clearing x:

$x=\frac{2.7*710}{1120} =1.71m$

c) The expression for the forces acting in the vertical direction is:

wboard + wmotor = F1 + F2

wmotor = F1 + F2 - wboard

wmotor = 410 + 710 - 200

wmotor = 920 N

d) The same that b)

$w_{motor} (\frac{l}{2} )+w_{board} x=F_{2} l\\x=\frac{2.7*710-200\frac{2.7}{2} }{920} =1.79m$

7 0

3 years ago