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3 years ago

A car accelerates from 6.00 m/s to 20.0 m/s, over a distance of 50.0 m. what is its rate of acceleration?

1 answer:

6 0

v² = u² + 2as 
2as = v² - u²
a = (v² - u²) / 2s 

a = (20.0² m²/s² - 6.00² m²/s²) / (2 * 50.0 m) 
a = (400 m²/s² - 36 m²/s²) / (100 m) 
a = (364 m²/s²) / (100 m) 
a = 3.64 m/s²

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Two identical loudspeakers are some distance apart. A person stands 5.80 m from one speaker and 3.90 m from the other. What is t

NikAS [45]

Answer:

f = 632 Hz

Explanation:

As we know that for destructive interference the path difference from two loud speakers must be equal to the odd multiple of half of the wavelength

here we know that

$\Delta x = (2n + 1)\frac{\lambda}{2}$

given that path difference from two loud speakers is given as

$\Delta x = 5.80 m - 3.90 m$

$\Delta x = 1.90 m$

now we know that it will have fourth lowest frequency at which destructive interference will occurs

so here we have

$\Delta x = 1.90 = \frac{7\lambda}{2}$

$\lambda = \frac{2 \times 1.90}{7}$

$\lambda = 0.54 m$

now for frequency we know that

$f = \frac{v}{\lambda}$

$f = \frac{343}{0.54} = 632 Hz$

7 0

3 years ago

When measuring accelerations with three different graphs (x-t, v-t, a-t) which gives the most reliable results and why?

kipiarov [429]

Answer:

the best graph to find the acceleration is v-t since calculating the slope averages the different experimental errors.

Explanation:

The different graphics depending on time give various information, let's examine what we can get from some

Graph of x -t. from this graph we can obtain the speed through the slope, but the acceleration is not directly obtainable

v-t chart. We can get the acceleration not through the slope and the distance traveled by the area under the curve. Obtaining acceleration is very accurate since it is an average that avoids possible errors in measurements. This is the best graph to find the acceleration

Graph of a-t In this graph the acceleration is a point on the Y axis, it gives some errors because it depends strongly on the possible experimental errors.

In conclusion, the best graph to find the acceleration is v-t since calculating the slope averages the different experimental errors.

5 0

3 years ago

If a star appears to be very red (like Betelgeuse), it is likely to be in which spectral class?

Kipish [7]

It would be spectral class M

hope this helps

7 0

3 years ago

Read 2 more answers

Really easy it's physics.

iragen [17]

I think it’s B because we aren’t looking for Vf