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Mashcka [7]
3 years ago
10

A car accelerates from 6.00 m/s to 20.0 m/s, over a distance of 50.0 m. what is its rate of acceleration?

Physics
1 answer:
Kitty [74]3 years ago
6 0
<span>v² = u² + 2as </span>
2as = v² - u² 
<span>a = (v² - u²) / 2s </span>

<span>a = (20.0² m²/s² - 6.00² m²/s²) / (2 * 50.0 m) </span>
<span>a = (400 m²/s² - 36 m²/s²) / (100 m) </span>
<span>a = (364 m²/s²) / (100 m) </span>
a = 3.64 m/s²
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The main water line enters a house on the first floor. The line has a gauge pressure of 1.94 x 105 Pa. (a) A faucet on the secon
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Answer

given,

gauge pressure =   1.94 x 10⁵ Pa

Pressure due to 4.90 m column of water

= ρ g h

= (4.90) x  (1000)  x (9.8) Pa

= 48020 Pa

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= 1.94 x 10⁵Pa - 48020 Pa

P_g= 145980 Pa

( b )

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P = ρ g h

1.94 x 10⁵  = h x(1000) x (9.8)

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A coin is placed on a large disk which rotates uniformly at a rate of 1 rot/s. The coefficient of friction between the coin and
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Answer:

r = 0.02 m

Explanation:

from the question we have :

speed = 1 rps = 1x 60 = 60 rpm

coefficient of friction (μ) = 0.1

acceleration due to gravity (g) = 9.8 m/s^{2}

maximum distance without falling off (r) = ?

to get how far from the center of the disk the coin can be placed without having to slip off we equate the formula for the centrifugal force with the frictional force on the turntable force

mv^2 / r =  m x g x μ

v^2 / r =  g x μ  .......equation 1

where

velocity (v) = angular speed (rads/seconds) x radius

angular speed (rads/seconds) = (\frac{2π}{60} ) x rpm

angular speed (rads/seconds) = (\frac{2 x π}{60} ) x 60 = 6.28 rads/ seconds

now

velocity = 6.28 x r = 6.28 r

now substituting the value of velocity into equation 1

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