A car accelerates from 6.00 m/s to 20.0 m/s, over a distance of 50.0 m. what is its rate of acceleration?

1 answer:

6 0

v² = u² + 2as 
2as = v² - u²
a = (v² - u²) / 2s 

a = (20.0² m²/s² - 6.00² m²/s²) / (2 * 50.0 m) 
a = (400 m²/s² - 36 m²/s²) / (100 m) 
a = (364 m²/s²) / (100 m) 
a = 3.64 m/s²

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