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arsen [322]
4 years ago
6

An observer that stands still as the electron moves by him, will observe ___.

Physics
1 answer:
muminat4 years ago
3 0

When charge is placed near to us whether it is stationary or if it is in motion then we can say it will produce electric field.

Now when charge is in motion then it will also produce electric current

So due to a moving charge there is some magnetic field also near it

it is given as

B = \frac{\mu_0 qv}{4\pi r^2}

So here we can say that nearby a moving charge we must have experience the effect of electric field as well as magnetic field

so the correct answer must be

<em>B) An electric & magnetic field</em>

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A 60-kg man uses an electric chair to carry him up the stairs. if the chair has a mass of 200 kg, what power must a motor genera
mrs_skeptik [129]
1200w that is the answer I don't really know
4 0
3 years ago
Read 2 more answers
Photosynthesis transforms molecules of water and carbon dioxide into Molecules of?
brilliants [131]
Into molecules of sugar and oxygen.
The complete reaction of the photosynthesis is in fact:
6CO_2+6H_2O \rightarrow C_6H_{12}O_6+6O_2
and the energy of the light coming from the sun is also used to make the reaction possible.
7 0
4 years ago
A car accelerates uniformly from rest to 20 m/sec in 5.6 sec along a level stretch of road. Ignoring friction, determine the ave
bonufazy [111]

Answer:

(a) P=33000W

(b) P=51000W

Explanation:

The average power is defined as the amount of work done during a time interval:

P=\frac{W}{t}(1)

According to work-energy theorem, the work done is equal to the change in kinetic energy. So, we have:

W=\Delta K\\W=K_f-K_0\\W=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}\\(2)

Recall that the weight is given by:

w=mg\\m=\frac{w}{g}(3)

The car accelerates uniformly from rest (v_0=0). Replacing (3) in (2), we have:

W=\frac{wv_f^2}{2g}

(a) Finally, we replace this in (1):

P=\frac{wv_f^2}{2gt}\\P=\frac{9000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=33000W

(b)

P=\frac{14000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=51000W

3 0
4 years ago
Forces holding particles together are strongest in a
Juli2301 [7.4K]
The answer may be pair or group
7 0
3 years ago
15) A 328-kg car moving at 19.1 m/s in the +x direction hits from behind a second car moving at 13 m/s in the same direction. If
kolbaska11 [484]

Answer:

Explanation:

Given that,

Mass of first car

M1= 328kg

The car is moving in positive direction of x axis with velocity

U1 = 19.1m/s

Velocity of second car

U2 = 13m/s, in the same direction as the first car..

Mass of second car

M2 = 790kg

Velocity of second car after collision

V2 = 15.1 m/s

Velocity of first car after collision

V1 =?

This is an elastic collision,

And using the conservation of momentum principle

Momentum before collision is equal to momentum after collision

P(before) = P(after)

M1•U1 + M2•U2 = M1•V1 + M2•V2

328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1

16534.8 = 328•V1 + 11929

328•V1 = 16534.8—11929

328•V1 = 4605.8

V1 = 4605.8/328

V1 = 14.04 m/s

The velocity of the first car after collision is 14.04 m/s

5 0
3 years ago
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