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3 years ago

How does the antenna work to detect the electromagnetic signal produced when radio stations broadcast

Physics

1 answer:

galina1969 [7]3 years ago

3 0

Answer:

The antenna which is a transmitting and receiving device emits energy from current as radio waves, it does this by attracting the radio waves which are a form of EMWs and converts it to small voltages which are amplified to the final voltage signal which hear

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A car with a speed of 50ms is stopped when its brakes are pressed. The displacement passed before stopping is 150 m. How much de

monitta

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3 years ago

How does a concave mirror form an image

vladimir2022 [97]

Answer:

The correct option is (c) "it bounces the light towards a focal point"

Explanation:

There are two types of spherical mirrors i.e. concave and convex.

A concave mirror is a type of spherical mirror that is curved inwards. For this type of mirror the rays of light are bounced back and converge to the focal point of the mirror.

So, the correct option is (c).

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3 years ago

As it rains and snows near mountaintops, the water is transferred from the atmosphere back onto ground. What natural force pulls

Semenov [28]

Gravity pulls the water down off the mountain, witch is run-off.

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4 years ago

Please help me!<br>each form of a characteristic is called what?

jeka94

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3 years ago

Read 2 more answers

You throw a ball straight up with an initial velocity of 15.0 m/s. It passes a tree branch on the way up at a height of 7.00 m.

Gwar [14]

Answer:

0.95 seconds

Explanation:

t = Time taken

u = Initial velocity = 15 m/s

v = Final velocity

s = Displacement

a = Acceleration = 9.81 m/s² (downward positive, upward negative)

Time taken by the ball to reach the maximum height

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-15}{-9.81}\\\Rightarrow t=1.52\ s$

Maximum height

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-15^2}{2\times -9.81}\\\Rightarrow s=11.47\ m$

Distance between maximum height of the ball and the branch is 11.47-7 = 4.46 m

So, the distance that will be covered on the way down is 4.46 m

Now

u = 0

s = 4.46

$s=ut+\frac{1}{2}at^2\\\Rightarrow 4.46=0\times t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{4.46\times 2}{9.81}}\\\Rightarrow t=0.95\ s$

Time taken by the ball from the maximum height to the tree branch is 0.95 seconds.

Total time taken from the moment the ball is thrown to reach the tree branch is 1.52+0.95 = 2.47 seconds

7 0

3 years ago