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SpyIntel [72]
3 years ago
8

Explain why the stars look different between Jane and John

Physics
1 answer:
Svetlanka [38]3 years ago
8 0
To summarize, Jane's star has a red light and is traveling towards the earth while John's star star has a blue light and is traveling away from the earth. ... The stars look different because they are traveling in different directions.
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The key differences between rotational kinematics and translational kinematics is: A. Rotational kinematics must specify an axis
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In Translational motion, the body moves in a straight line whereas in Rotational motion, the body moves in a circular path.

<h3>Differences between rotational kinematics and translational kinematics</h3>

In Translational motion, the body moves in a straight line and the body same displacement in equal interval of time while on the other hand, in Rotational motion, the body moves in a circular path and the body travels same angular displacement in equal interval of time..

Learn more about motion here: brainly.com/question/453639

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2 years ago
For a solution to be a physical solution, it must satisfy several criteria. First, it must be continuous everywhere. Second, it
Zigmanuir [339]

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Explanation:

solution

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3 years ago
List 4 ways to separate mixtures
Sergeeva-Olga [200]
1.Paper Chromatography. This method is often used in the food industry. ...

2.Filtration. This is a more common method of separating an insoluble solid from a liquid. ...

3.Evaporation. ...

4Simple distillation. ...
Fractional distillation.
7 0
3 years ago
What would we need to do to make an electromagnet strong enough to move cars and trains
SVEN [57.7K]

Answer:

The combined magnetic force of the magnetized wire coil and iron bar makes an electromagnet very strong. In fact, electromagnets are the strongest magnets made. An electromagnet is stronger if there are more turns in the coil of wire or there is more current flowing through it.

5 0
2 years ago
At a depth of 1030 m in Lake Baikal (a fresh water lake in Siberia), the pressure has increased by 100 atmospheres (to about 107
dangina [55]

Answer:

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

Explanation:

The bulk modulus is represented by the following differential equation:

K = - V\cdot \frac{dP}{dV}

Where:

K - Bulk module, measured in pascals.

V - Sample volume, measured in cubic meters.

P - Local pressure, measured in pascals.

Now, let suppose that bulk remains constant, so that differential equation can be reduced into a first-order linear non-homogeneous differential equation with separable variables:

-\frac{K \,dV}{V} = dP

This resultant expression is solved by definite integration and algebraic handling:

-K\int\limits^{V_{f}}_{V_{o}} {\frac{dV}{V} } = \int\limits^{P_{f}}_{P_{o}}\, dP

-K\cdot \ln \left |\frac{V_{f}}{V_{o}} \right| = P_{f} - P_{o}

\ln \left| \frac{V_{f}}{V_{o}} \right| = \frac{P_{o}-P_{f}}{K}

\frac{V_{f}}{V_{o}} = e^{\frac{P_{o}-P_{f}}{K} }

The final volume is predicted by:

V_{f} = V_{o}\cdot e^{\frac{P_{o}-P_{f}}{K} }

If V_{o} = 1\,m^{3}, P_{o} - P_{f} = -10132500\,Pa and K = 2.3\times 10^{9}\,Pa, then:

V_{f} = (1\,m^{3}) \cdot e^{\frac{-10.1325\times 10^{6}\,Pa}{2.3 \times 10^{9}\,Pa} }

V_{f} \approx 0.996\,m^{3}

Change in volume due to increasure on pressure is:

\Delta V = V_{o} - V_{f}

\Delta V = 1\,m^{3} - 0.996\,m^{3}

\Delta V = 0.004\,m^{3}

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

8 0
3 years ago
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