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solniwko [45]
3 years ago
6

Explain why the invention of the microscope was important in the study of cells

Chemistry
2 answers:
Brrunno [24]3 years ago
8 0
It brought us closer to a world that we otherwise wouldn't be able to see. We can now study and observe cells and other micro molecules.
Tpy6a [65]3 years ago
6 0
The invention of the microscope was important to study the cell because it allowed the cells to be viewed due to the power of magnification. without a microscope we would not know all that we do know about the cell. <span />
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Which is the correct answer???????
hichkok12 [17]
The answer is the first option (a)
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3 years ago
How many atoms of carbon are present in 1.0 g of c6h12o6?
REY [17]
I don't know Im just Trying to get points somehow
4 0
3 years ago
What is the average mass of an electron? A. 1 amu B. 1,837 amu C. 1/1,837
diamong [38]

Answer:

C. 1/1,837

Explanation:

3 0
3 years ago
Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi
xenn [34]

Conjugate base of Propanoic acid (CH_{3}CH_{2}COOH is propanoate where -COOH group gets converted to -COO^{1-}. The structure of conjugate base of Propanoic acid is shown in the diagram.

The p^{H} above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

p^{H}= p^{k_{a}+ log\frac{[Conjugate base]}{[acid]}=4.9+log\frac{90}{10}=5.85

As 90% conjugate base is present, so propanoic acid present 10%.

8 0
3 years ago
Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.
Svetradugi [14.3K]

Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100

Given:

Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur

Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%

\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%

\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%

Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

3 0
3 years ago
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