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Gekata [30.6K]
4 years ago
12

A student of mass 40kg takes 10s to run up a flight of 50steps. If each step is 15cm high, calculate the Potential Energy of the

student at the maximum height.​
Physics
1 answer:
astra-53 [7]4 years ago
3 0

Answer:

2943 J

Explanation:

Potential energy = mass x acceleration due to gravity x height in meters

(P.E. = mgh)

Substitute the given numbers: (I take acceleration due to gravity as 9.81 m s^-2)

PE = 40 x 9.81 x (0.15x50)

PE = 2943 J

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A nonconducting sphere of diameter 10.0 cm carries charge distributed uniformly inside with charge density of +5.50 µC/m3 . A pr
VLD [36.1K]

Answer:

t = 2.58*10^-6 s

Explanation:

For a nonconducting sphere you have that the value of the electric field, depends of the region:

rR:\\\\E=k\frac{Q}{r^2}

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

R: radius of the sphere = 10.0/2 = 5.0cm=0.005m

In this case you can assume that the proton is in the region for r > R. Furthermore you use the secon Newton law in order to find the acceleration of the proton produced by the force:

F=m_pa\\\\qE=m_pa\\\\k\frac{qQ}{r^2}=m_pa\\\\a=k\frac{qQ}{m_pr^2}

Due to the proton is just outside the surface you can use r=R and calculate the acceleration. Also, you take into account the charge density of the sphere in order to compute the total charge:

Q=\rho V=(5.5*10^{-6}C/m^3)(\frac{4}{3}\pi(0.05m)^3)=2.87*10^{-9}C\\\\a=(8.98*10^9Nm^2/C^2)\frac{(1.6*10^{-19}C)(2.87*10^{-9}C)}{(1.67*10^{-27}kg)(0.05m)^2}=9.87*10^{11}\frac{m}{s^2}

with this values of a you can use the following formula:

a=\frac{v-v_o}{t}\\\\t=\frac{v-v_o}{a}=\frac{2550*10^3m/s-0m/s}{9.87*10^{11}m/s^2}=2.58*10^{-6}s

hence, the time that the proton takes to reach a speed of 2550km is 2.58*10^-6 s

3 0
3 years ago
Explain how columns can be used and set up to increase the effectiveness of business documents.
Usimov [2.4K]
You can put the name of the product and the price and add another column and add all of your expenses<span />
3 0
3 years ago
If you could help me out that would be fantastic.?!!!
Volgvan
It's either C. Or B.
3 0
4 years ago
the half-life of iodine-131 is 8.1 days. how much time had passed if i only have one-fourth of the original sample?​
morpeh [17]

Answer:

16.2 days

Explanation:

Find the number of halflives:

1/2   *  1/2 =  1/4     so <u>two</u>   halflives have passed

   2 * 8.1 days = 16.2 days

8 0
1 year ago
For problems that involve an object accelerating along an inclined plane, how can the weight be used to determine the force comp
irakobra [83]

Answer:

C

Explanation:

Ed2020

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4 years ago
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