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3 years ago

The photo shows a person pumping gasoline into a car

Physics

1 answer:

miv72 [106K]3 years ago

6 0

Answer:

It is CHEMICAL TO MECHANICAL because gas is a chemical which is transferred to mechanical technologies

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A 200-turn flat coil of wire 30.0 cm in diameter acts as an antenna for FM radio at a frequency of 100 MHz. The magnetic field o

dalvyx [7]

Answer:

a) 8.4×10^-12W

b) 5.65 ×10^ -3V

c) 1.01 ×10^ -12 F

Explanation: Given:

Radius r = d/2 = 30/2=15cm= 0.15m

Maximum feild strength = Bo= 10^-12 T

Permiability of vacuum, Uo = 4pi×10^-7

I = CBo/2Uo = (3 ×10^8×(10^-12)^2)/ (4 ×3.142×10^-7)

I = 1.19×10^-10W/m^2

The intensity I = > P/A = p = IA = I(4pi^2)

P = 1.19×10^-10 × 3.142 × (0.15^2)

P = 8.4 × 10^-12W

b) Given: f = 100Mhz= 100×10^6hz

Number of turns in the coil, N = 200

Time of cycle, T = 1/f = 1/ 100×10^6

T = 10^-8 seconds

Change in t= 1/4T = 1/4×10^-8 = 2.5 ×10^-9sec

E = (N×change in B×A)/ change in t

E = (NBopir^2)/change in t

E = (200 ×10^-12× 3.142 ×(0.15^2))/ (2.5×10^-9)

E = 5.65 ×10^-3V

c) Self inductance L = 2.5UH=2.5×10^-6H

Resonant frequency, fo= 1/(2pisqrt(LC))

C= 1/(4×3.142×( 2.5×10^-6)× (100×10^6)^2

C = 1.01×10^-12F

3 0

4 years ago

Read 2 more answers

Do I have to choose physics to be an architect

horrorfan [7]

Physics is a very important part of Architecture. It helps you to understand how forces work on things that you build, so that they don't collapse. So yes, you do.

7 0

3 years ago

Read 2 more answers

What is Humpty Dumpty's momentum if he has a mass of 56kg and is walking to the wall at a rate of 3 m/s?

Sophie [7]

Answer:

168

Explanation:

56 x 3

have a nice day

5 0

3 years ago

A snake slithered across the sidewalk in between two sign posts. At the first sign post his speed was

masha68 [24]

This is an example of Uniform Speed

EXPLANATION

Uniform Speed => no change in speed

Uniform Accelerations Speed => There is a change in speed, but the acceleration remains the same.

#LearnWithEXO

5 0

3 years ago

A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s,

Andreyy89

The final position of the car is 385 m.

Explanation:

We know the formula :

s = $ut +$ $\frac{1}{2} at^{2}$

where,

s = distance

u = initial velocity = 5.1 m/s

t = time taken = 14 sec

a = acceleration = 3.2 m/ $s^{2}$

Solving:

s = 5.1* 14 + $\frac{1}{2}$ * 3.2 * $14^{2}$

∴ s = 385 m

Hence the final position of the car is 385 m.

3 0

3 years ago