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Serhud [2]
3 years ago
10

If a 2.8 mole sample of gas initially occupies 54 L at 3.8 atm, what is its temperature in K?

Chemistry
1 answer:
leonid [27]3 years ago
7 0

Answer: 893.7K

Explanation:

From the question, we obtained the following:

V = 54L

n = 2.8moles

P = 3.8 atm

R = 0.082atm.L/mol /K

T =?

Applying the ideal gas equation, we have:

PV = nRT

T = PV /nR

T = (3.8x54)/(2.8x0.082)

T = 893.7K

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If the volume occupied by 0.500 mol of nitrogen gas at 0°C is 11.2 L, then the volume occupied by 2.00 mol of nitrogen gas at th
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3 years ago
If the solubility of a gas is 10.5 g/L at 525 kPa pressure, what is the solubility of the gas when the pressure is 225 kPa? Show
Talja [164]

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4.5 g/L.

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S is the solubility of the gas.

  • At two different pressures, we have two different solubilities of the gas.

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