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insens350 [35]
3 years ago
13

A scientist notices that an oil slick floating on water when viewed from above has many different colors reflecting off the surf

ace, making it look rainbow-like (an effect known as iridescence). She aims a spectrometer at a particular spot and measures the wavelength to be 750 nm (in air). The index of refraction of water is 1.33.
(a) The index of refraction of the oil is 1.20. What is the minimum thickness t of the oil slick at that spot?

(b) Suppose the oil had an index of refraction of 1.50. What would the minimum thickness t be now?
Physics
1 answer:
Tasya [4]3 years ago
3 0

Answer:

<em>The correct answer is (a) 312.5nm and (b) 125nm</em>

Explanation:

<em>The first step to take is to find The minimum thickness of the slick of the oil</em>

<em>Given that,</em>

<em>(a) tmin  λ/2n </em>

<em>We substitute 750nm ( in air) for λ and 1.20 for n for the expression of  minimum thickness t of the oil slick at that spot</em>

<em>thus,</em>

<em>tmin = (750nm)/2(1.2) = 312.5nm</em>

<em>The minimum thickness of the oil slick at that spot is =312.5nm</em>

<em>(B) we find the minimum thickness t </em>

<em>The minimum thickness of the oil slick at the spot will be calculated by,</em>

<em>tmin = λ/4n</em>

<em>we then 750nm ( in air) for λ and 1.50 for n  in the expression for the minimum thickness of the slick of the oil.</em>

<em>tmin = (750nm)/4 (1.5) = 125nm</em>

<em>Therefore the minimum thickness t will now be = 125nm</em>

<em />

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You are in a boat that is 1400 kg. The current is 1500N and is pushing you back. If you have an acceleration of 3 m/s^2 what is
aleksandrvk [35]

Answer: The force of the engines is 5700N

Explanation:

By the second Newton's law, we have that:

F = m*a

Force equals mass times acceleration.

In this case, we have:

m = 1400kg

a = 3 m/s^2

And the force will be equal to the force of the engines, f, plus the force of  the current, -1500 N (because this is pushing you back, so it is in the opposite direction than f), then we have:

F = f - 1500N

Then we have the equation:

f - 1500N = 1400kg*3m/s^2 = 4200N

f - 1500N = 4200N

f = 4200N + 1500N = 5700N

The force of the engines is 5700N

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2 years ago
A 20-cm-long stick of m = 0.600 kg is lifted by a rope tied 5.0 cm from the upper end. The other end touches a smooth floor. The
Liula [17]

Answer:

https://www.chegg.com/homework-help/questions-and-answers/part-20-cm-long-stick-m-0400-kg-lifted-rope-tied-70-cm-upper-end-end-touches-smooth-floor--q81268572

3 0
2 years ago
An object is thrown with a force of 30 Newtons and ends up with an acceleration of 3 m/s ^ 2 due to that throw. What is the mass
jonny [76]

Answer:

F=30N

a= 3m/s^2

m=?

F=ma

30=m(3)

30/3=m

m=10kg

The mass of the ball is 10kg

4 0
3 years ago
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

    The mass of the arm is m_a  = 4.0 \  kg

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

       r = \frac{l}{2}

=>    r = \frac{ 0.7}{2}  

=>    r = 0.35 \ m  

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

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2 years ago
When it gets that hot the evergreens can explode?
Ghella [55]
If you mean the tree, evergreen trees can exploded if theres extreme stress on the trunk
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3 years ago
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