Answer: The force of the engines is 5700N
Explanation:
By the second Newton's law, we have that:
F = m*a
Force equals mass times acceleration.
In this case, we have:
m = 1400kg
a = 3 m/s^2
And the force will be equal to the force of the engines, f, plus the force of the current, -1500 N (because this is pushing you back, so it is in the opposite direction than f), then we have:
F = f - 1500N
Then we have the equation:
f - 1500N = 1400kg*3m/s^2 = 4200N
f - 1500N = 4200N
f = 4200N + 1500N = 5700N
The force of the engines is 5700N
Answer:
https://www.chegg.com/homework-help/questions-and-answers/part-20-cm-long-stick-m-0400-kg-lifted-rope-tied-70-cm-upper-end-end-touches-smooth-floor--q81268572
Answer:
F=30N
a= 3m/s^2
m=?
F=ma
30=m(3)
30/3=m
m=10kg
The mass of the ball is 10kg
Complete Question
An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.
Answer:
The torque is 
Explanation:
From the question we are told that
The mass of the steel ball is 
The length of arm is 
The mass of the arm is 
Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

=>
=>
Generally the magnitude of torque about the athlete shoulder is mathematically represented as

=> 
=> 
If you mean the tree, evergreen trees can exploded if theres extreme stress on the trunk