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insens350 [35]
4 years ago
13

A scientist notices that an oil slick floating on water when viewed from above has many different colors reflecting off the surf

ace, making it look rainbow-like (an effect known as iridescence). She aims a spectrometer at a particular spot and measures the wavelength to be 750 nm (in air). The index of refraction of water is 1.33.
(a) The index of refraction of the oil is 1.20. What is the minimum thickness t of the oil slick at that spot?

(b) Suppose the oil had an index of refraction of 1.50. What would the minimum thickness t be now?
Physics
1 answer:
Tasya [4]4 years ago
3 0

Answer:

<em>The correct answer is (a) 312.5nm and (b) 125nm</em>

Explanation:

<em>The first step to take is to find The minimum thickness of the slick of the oil</em>

<em>Given that,</em>

<em>(a) tmin  λ/2n </em>

<em>We substitute 750nm ( in air) for λ and 1.20 for n for the expression of  minimum thickness t of the oil slick at that spot</em>

<em>thus,</em>

<em>tmin = (750nm)/2(1.2) = 312.5nm</em>

<em>The minimum thickness of the oil slick at that spot is =312.5nm</em>

<em>(B) we find the minimum thickness t </em>

<em>The minimum thickness of the oil slick at the spot will be calculated by,</em>

<em>tmin = λ/4n</em>

<em>we then 750nm ( in air) for λ and 1.50 for n  in the expression for the minimum thickness of the slick of the oil.</em>

<em>tmin = (750nm)/4 (1.5) = 125nm</em>

<em>Therefore the minimum thickness t will now be = 125nm</em>

<em />

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The Sun delivers an average power of 1.575 W/m2 to the top of Neptune's atmosphere. Find the magnitudes of max and max for the e
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B_m=\sqrt{\dfrac{2\mu_0I}{c}}\\\Rightarrow B_m=\sqrt{\dfrac{2\times 4\pi \times 10^{-7}\times 1.575}{3\times 10^8}}\\\Rightarrow B_m=1.1486813808\times 10^{-7}\ T

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3 years ago
Explain how polarization of a cell increases the cell's internal resistance.<br>(2<br>2.​
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Answer:

Explanation: The chemical action that occurs in the cell while the current is flowing causes hydrogen bubbles to form on the surface of the anode. This action is called POLARIZATION. Some hydrogen bubbles rise to the surface of the electrolyte and escape into the air, some remain on the surface of the anode. If enough bubbles remain around the anode, the bubbles form a barrier that increases internal resistance. When the internal resistance of the cell increases, the output current is decreased and the voltage of the cell also decreases.

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   A third method is to use a material that will absorb the hydrogen, such as calcium. The calcium releases hydrogen during the charging process. All three methods remove enough hydrogen so that the cell is practically free from polarization.

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   When the external circuit is removed, the current ceases to flow, and, theoretically, all chemical action within the cell stops. However, commercial zinc contains many impurities, such as iron, carbon, lead, and arsenic. These impurities form many small electrical cells within the zinc electrode in which current flows between the zinc and its impurities. Thus, the chemical action continues even though the cell itself is not connected to a load.

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6 0
3 years ago
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Ipatiy [6.2K]

Answer:

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This value should also be equal to KE2, which can be calculated using the conditions after the collision.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x from the equation is 17.16 cm/s.

Hence, the answer is 17.16 cm/s. 
6 0
3 years ago
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