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Kaylis [27]
3 years ago
10

fan can accelerate from the starting blocks to running 11 m/s down the track in 5 seconds. what is her acceleration?

Physics
2 answers:
s344n2d4d5 [400]3 years ago
8 0

Answer: Got It...

Explanation: <em>Fan can accelerate from the starting blocks to running 11 m/s down the track in 5 seconds. </em>

Delvig [45]3 years ago
3 0
At a discount furniture store, Chris offered a salesman $600 for a couch and a chair. The offer includes the 8% sales tax. If the salesman accepts the offer, what would be the price of the furniture, to the nearest dollar, before tax? Please show you work.
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Which of the following is a theory stating that one plate is forced beneath another plate?
morpeh [17]

Answer:

theroy of plate tectonics

7 0
3 years ago
The pressure on a fluid at rest in a pipe increases by 20 Pa. How does this change in pressure affect the pressure on the fluid
timofeeve [1]

Answer:The change in pressure can affect the pressure on the fluid through the radius and diameter of the pipe.

r^² x Pressure (pa).

Therefore the narrower the other part of the pile, the greater the pressure on the fluid at such part, the wider in other part the lesser the pressure on the fluid at this part.

Explanation:

4 0
3 years ago
A ball is thrown horizontally from the top of a 60.0-m building and lands 100.0 m from the base of thebuilding. Ignore air resis
Bumek [7]

Answer:

a)3.5s

b)28.57m/S

c)34.33m/S

d)44.66m/S

Explanation:

Hello!

we will solve this exercise numeral by numeral

a) to find the time the ball takes in the air we must consider that vertically the ball experiences a movement with constant acceleration whose value is gravity (9.81m / S ^ 2), that the initial vertical velocity is zero, we use the following equation for a body that moves with constant acceleration

Y= VoT+0.5gt^{2}

where

Vo = Initial speed =0

T = time

g=gravity=9.81m/s^2

y = height=60m

solving for time

Y=0.5gt^2\\t=\sqrt{\frac{Y}{0.5g} } \\t=\frac{60}{0.5(9.81)} \\

T=3.5s

b)The horizontal speed remains constant since there is no horizontal acceleration. with the value of the distance traveled (100m) and the time that lasts in the air (3.5s) we estimate the horizontal speed

V=\frac{x}{t} =\frac{100}{3.5}=28.57m/s

c)

to find the final vertical velocity we use the equations for motion with constant velocity as follows

Vf=Vo+g.t    

Vf=0+(9.81 )(3.5)=34.335m/S          

d)Finally, to find the resulting velocity, we add the horizontal and vertical velocities vectorially, this is achieved by finding the square root of the sum of its squares

V=\sqrt{Vx^2+Vy^2} =\sqrt{34.33^2+28.57^2} =44.67m/S

7 0
3 years ago
In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon
Contact [7]

Complete Question

In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon, causing a red glow in and around it. It is hypothesized that this event created the crater Giordano Bruno, which is right on the edge of the area we can usually see from Earth.

How long after the asteroid hit the Moon,which is 3.84 *10^5 km away ,would the light first arrive on the earth in seconds

Answer:

The time it would take is  t = 1.28 \ sec

Explanation:

The objective of this question is to obtain the time the light would arrive earth

      We are told that the distance from moon to  earth is  

                  D = 3.84*10^5km = 3.84*10^5 * 1000 = 3.84*10^8m

Now generally time is mathematically represented as

                          t = \frac{D}{c}

The c here is the speed of light which has a value of c = 3*10^8 m/s

        Now substituting values

                        t = \frac{3.84 * 10^8 }{3*10^8}

                           = 1.28 \ sec

7 0
3 years ago
Read 2 more answers
Iwill need to use more force to stopa<br> O Lighter mass<br> O Heavier mass
trasher [3.6K]

Answer:

a heavier mass

Explanation:

7 0
3 years ago
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