Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .
1) nuclear fusion
During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. During this process, radiant energy is released.
Set this up as a proportion.
.002 m^3/20 degrees = x/50 degrees
solve for x
x = .005 m^3
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Answer:
112.23 m
Explanation:
Displacement is the final position minus the initial position.
Δx = x − x₀
Δx = 100.1 m − (-12.13 m)
Δx = 112.23 m
Explanation:
Watts are defined as 1 Watt = 1 Joule per second (1W = 1 J/s)
which means that 1 kW = 1000 J/s. A Watt is the amount of energy (in Joules) that an electrical device (such as a light) is burning per second that it's running.
