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Law Incorporation [45]
3 years ago
8

Compare the distance-time graph for a fast-moving object with the distance time graph of a slower moving object.

Physics
1 answer:
SSSSS [86.1K]3 years ago
6 0
The distance vs time graph of a faster moving object would have a greater slope than that of a slower moving one. The object would move a greater distance per unit time
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You jump off a platform 134 m above the Neuse River. After you have free-fallen for the first 40 m, the bungee cord attached to
omeli [17]

Answer:

The acceleration at lowest point is 19.62 m/s^2

Explanation:

Conservation of energy is an concept in which it is stated that the energy of an isolated object remains the same. Energy changes from one form to another.

Lets Assume

Constant of string is K

By using the conservation of energy we will have the following equation

1/2 x 80^2 x K = m x 9.81 x 120

3200 K =  1177.2 m

K = 1177.2 m / 3200

K = 0.368 m

At the lowest point we will have

a = ( K x X - m x g ) / m

a = ( 0.368 m x 80 - m x 9.81 ) / m

a = 19.62 m / s^2

So, the acceleration at lowest point is 19.62 m/s^2

7 0
3 years ago
Read 2 more answers
What is the acceleration of a 10kg mass pushed by a 5N force?​
GenaCL600 [577]

Answer:

<h2>0.5 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

From the question we have

a =  \frac{5}{10} =  \frac{1}{2}   \\  = 0.5

We have the final answer as

<h3>0.5 m/s²</h3>

Hope this helps you

5 0
3 years ago
How to read a vernier calipers?
RideAnS [48]

Answer:

I'll write it below

Explanation:

1) understand the parts.

2)read the scales

3)check the scale of your smallest divisions

4)clean the object you are measuring

5)If you have, unlock the screw

6)close the jaws

I hope this satisfies you sir.

If you have any questions related to this please feel free to ask me. I hope u will follow me and make this the brainliest answer.

7 0
3 years ago
Read 2 more answers
A constant voltage of 12.00 V has been observed over a certain time interval across a 1.20 H inductor. The current through the i
kiruha [24]

Answer:

The time is 0.5 sec.

Explanation:

Given that,

Voltage V= 12.00 V

Inductance L= 1.20 H

Current = 3.00 A

Increases rate = 8.00 A

We need to calculate change in current

\Delta A = 8.00-3.00= 5.00\ A

We need to calculate the time interval

Using formula of inductor

V=L\dfrac{\Delta A}{\Delta t}

\Delta t =\dfrac{L\Delta A}{V}

Where, \Delta A = change in current

V = voltage

L = inductance

Put the value into the formula

\Delta t=\dfrac{1.20\times5.00}{12.00}

\Delta t=0.5\ sec

Hence, The time is 0.5 sec.

5 0
3 years ago
This is a machine that converts electrical energy into mechanical energy.
Yuri [45]
<h2>Answer:</h2>

Motor

<h2>Explanation:</h2>

A motor is a machine that converts electrical energy into mechanical energy. In motors, electric energy is converted into mechanic energy when a magnetic torque acts on a conductor that carries a current. There are different types of motors like DC and AC motors. The moving part of a motor is called the rotor while the stationary part is called stator

8 0
3 years ago
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