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Law Incorporation [45]
3 years ago
8

Compare the distance-time graph for a fast-moving object with the distance time graph of a slower moving object.

Physics
1 answer:
SSSSS [86.1K]3 years ago
6 0
The distance vs time graph of a faster moving object would have a greater slope than that of a slower moving one. The object would move a greater distance per unit time
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What is mass loss and how does it figure in the death of a star? is the sun undergoing mass loss
Debora [2.8K]

111122 is the mass of the star

8 0
3 years ago
Suppose a capacitor is fully charged by a battery and then disconnected from the battery. The positive plate has a charge +q and
dimaraw [331]

Answer:-q

Explanation:

Given

Capacitor is charged to a battery and capacitor acquired a charge of q i.e.

+q on Positive Plate and -q on negative Plate.

If the plate area is doubled and the plate separation is reduced to half its initial separation then capacitor becomes four times of initial value because capacitor is given by

c=\epsilon_0 \cdot \frac{A}{d}

where A=area of capacitor plate

d=Separation between plates

This change in capacitance changes the Potential such that new charge on the negative plate will remain same -q

8 0
3 years ago
Can you explain hooks law in simple words?
dedylja [7]

Answer:

The extension of a material or a spring is its increase in length when pulled. Hooke’s Law says that the extension of an elastic object is directly proportional to the force applied to it. In other words:

Explanation:

7 0
2 years ago
Read 2 more answers
The energy flow per unit time per unit area (S) of an electromagnetic wave has an average value of 310 mW/m2. The maximum value
Aleksandr-060686 [28]

Answer:

5.096*10^-8

Explanation:

Given that

The average value of the electromagnetic wave is 310 mW/m²

To find the maximum value of the magnetic field the wave is closest to, we say

Emax = √Erms

Emax = √[(2 * 0.310 * 3*10^8 * 4π*10^-7)]

Emax = √233.7648

Emax = 15.289

Now, with our value of maximum electromagnetic wave gotten, we divide it by speed of light to get our final answer

15.289 / (3*10^8) = 5.096*10^-8 T

Suffice to say, The maximum value of the magnetic field in the wave is closest to 5.096*10^-8

6 0
2 years ago
During 57 seconds of use, 330 C of charge flow through a microwave oven. Compute the size of the electric current.
swat32

Answer:

5.78amps

Explanation:

Given data

Time t= 57 seconds

Charge Q= 330C

Current I= ??

The expression for the electric current is given as

Q= It

Substituting we have

330= I*57

I= 330/57

I=5.78 amps

Hence the current is 5.78amps

3 0
3 years ago
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