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Law Incorporation [45]
3 years ago
8

Compare the distance-time graph for a fast-moving object with the distance time graph of a slower moving object.

Physics
1 answer:
SSSSS [86.1K]3 years ago
6 0
The distance vs time graph of a faster moving object would have a greater slope than that of a slower moving one. The object would move a greater distance per unit time
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Write the ratio of the following?<br><br>CaCO3<br>C2H6<br>Fe(NO3)3​
Triss [41]

Answer:

C2H6 up the road to be with its own in

4 0
2 years ago
50 grams of ice cubes at -15°C are used to chill a water at 30°C with mass mH20 = 200 g. Assume that the water is kept in a foam
Arada [10]

Answer : The final temperature is, 25.0^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ice = 2.09J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ice = 50 g

m_2 = mass of water = 200 g

T_f = final temperature = ?

T_1 = initial temperature of ice = -15^oC

T_2 = initial temperature of water = 30^oC

Now put all the given values in the above formula, we get:

50g\times 2.09J/g^oC\times (T_f-(-15))^oC=-200g\times 4.184J/g^oC\times (T_f-30)^oC

T_f=25.0^oC

Therefore, the final temperature is, 25.0^oC

5 0
3 years ago
Alguien me ayuda con calculos estequiometricos?
ruslelena [56]

Answer:

SURE!!!...

But what to calculate!!!....

5 0
3 years ago
A 29 foot ladder leans against a building so that the angle between the ground and the ladder is 75 ∘ . How high does the ladder
Aloiza [94]

Answer:

28.01m

Explanation:

Opp/Hyp = Sin

Sin 75 = x/29

x = 29 sin 75

x = 28.01m

3 0
3 years ago
Problem A spring was at its resting position where it is attached to a wall at its left side and a block at its right side as sh
puteri [66]

Answer:

F = 19.1 N

Explanation:

To find the force exerted by the string on the block you use the following formula:

F=kx  (1)  

k: spring constant = 95.5 N/m

x: displacement of the block from its equilibrium position = 0.200 m

you replace the values of k and x in the equation (1):

F=(95.5N/m)(0.200m)=19.1N

Hence, the force exterted on the block is 19.1 N

 

8 0
3 years ago
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