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daser333 [38]
4 years ago
6

To how much water should 250 mL of 12 M hydrochloric acid be added to produce a 4.0 M solution?

Chemistry
1 answer:
likoan [24]4 years ago
6 0

Answer:

500ml water

Explanation:

Molarity x Volume in liters (concentrated soln) = Molarity x Volume (diluted soln) ∴

250ml X 12M HCl =  4M x Volume of diluted solution

=> Volume of diluted solution = (250ml)(12M)/(4m) = 750 ml final solution vol. after mixing.

So the amount of water added to the 250ml of 12M acid = 750ml - 250ml = 500ml of water.

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Determine the number of moles of oxygen atoms in each of the following.
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Part 2: 2.01 moles of N_2O contains 2.01 moles of oxygen atoms.

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<u>Part 1:</u> 4.93 mol H_2O_2

In 1 mole of H_2O_2, there are 2 atoms of hydrogen and 2 atoms of oxygen.

As, 1 mole of H_2O_2 contains 2 moles of oxygen atoms.

So, 4.93 moles of H_2O_2 contains 4.93\times 2=9.86 moles of oxygen atoms.

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As, 1 mole of N_2O contains 1 mole of oxygen atoms.

So, 2.01 moles of N_2O contains 2.01\times 1=2.01 moles of oxygen atoms.

Thus, 2.01 moles of N_2O contains 2.01 moles of oxygen atoms.

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