Question

An unknown substance has a mass of 18.3 g . When the substance absorbs 1.647×102 j of heat, the temperature of the substance is raised from 25.0 ∘c to 45.0 ∘c . What is the most likely identity of the substance?

Answer 1

Mass of the substance (m) = 18.3 g

Initial temperature T1 = 25 C

Final temperature T2 = 45 C

Heat absorbed by the substance (Q) = 1.647*10^2 J

Specific heat = c

Formula:

Q = m*c*ΔT

  = m*c*(T2-T1)

c = Q/m*(T2-T1) = 1,647*10^2 J/18.3 g *(45-25)C

c = 0.45 J/g C

The substance with a specific heat capacity of 0.45 J/g C is iron.