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Svetlanka [38]
3 years ago
11

Which of the following are TRUE concerning rectifier circuits? Select all that apply.

Engineering
1 answer:
Dovator [93]3 years ago
8 0

Explanation:

a. The output of an ideal full wave rectifier is zero volts only when the input is zero volts.

True

The output of an ideal full wave rectifier is zero volts only when the input is zero since 1st diode is forward biased during one half cycle of the input and 2nd diode is forward biased during the other half cycle of the input therefore, it fully utilizes both the input cycles so the output voltage is only zero when the input is zero.

b. Half-wave rectifier circuits need a minimum of 4 diodes to operate.

False

A Half-wave rectifier circuits need a minimum of 1 diode to operate, whereas a full-wave bridge rectifier need minimum of 4 diodes to operate.

c. In an ideal full wave bridge rectifier, half of the diodes are in the ON state and half of the diodes are in the OFF state at any given time the input voltage is not zero.

True

A full-wave bridge rectifier consists of 4 diodes, where 2 diodes are functional in half of the cycle(so the other 2 are off) and other 2 diodes are functional in the other half cycle( so the other 2 are off).

d. The output of an ideal half wave rectifier is zero volts only when the input is zero volts.

False

The output of an ideal half wave rectifier is zero during half of the cycle when the diode is reversed biased and doesn't conduct even though input voltage is not zero volts at this point.

e. A turn-on voltage of a diode (y,) greater than zero can cause the output of a full wave rectifier to be zero volts even when the input is not zero volts.

False

A turn-on voltage of a diode (y,) greater than zero cannot cause the output of a full wave rectifier to be zero rather there will be a little voltage drop across the output of full wave rectifier due to this turn-on voltage of diode which is usually 0.7 volts for silicon based diodes.

f. An advantage of the half wave rectifier is that is can use a smoothing capacitor, while a full wave rectifier cannot.

False

Smoothing capacitor can be used in both half wave rectifier as well as full wave rectifier.

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Consider fully developed laminar flow in a circular pipe. If the viscosity of the fluid is reduced by half by heating while the
gladu [14]

Answer:

The pressure drop across the pipe also reduces by half of its initial value if the viscosity of the fluid reduces by half of its original value.

Explanation:

For a fully developed laminar flow in a circular pipe, the flowrate (volumetric) is given by the Hagen-Poiseulle's equation.

Q = π(ΔPR⁴/8μL)

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If all the other parameters are kept constant, the pressure drop across the circular pipe is directly proportional to the viscosity of the fluid flowing in the pipe

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K = (8QL/πR⁴) = constant (for this question)

ΔP = Kμ

K = (ΔP/μ)

So, if the viscosity is halved, the new viscosity (μ₁) will be half of the original viscosity (μ).

μ₁ = (μ/2)

The new pressure drop (ΔP₁) is then

ΔP₁ = Kμ₁ = K(μ/2)

Recall,

K = (ΔP/μ)

ΔP₁ = K(μ/2) = (ΔP/μ) × (μ/2) = (ΔP/2)

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Hope this Helps!!!

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Option D

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PSYCHO15rus [73]

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