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3 years ago

5. Name two health problems that fume can cause? a).... b)......

Engineering

2 answers:

hjlf3 years ago

8 0

Answer inflamed throat and nose problems, sever cases, asthma like symtoms

Explanation:

You got choked by poison that isnt meant to smell for prolonged seconds

Vlad [161]3 years ago

5 0

Answer:

A) Cancer of the Lungs

B)Larynx and Urinary Tract, as well as nervous system and kidney damage

Explanation:

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Thoughts on Anime?<br> Whats your fav

nlexa [21]

Is miraculous ladybug one

5 0

3 years ago

Read 2 more answers

For laminar flow over a hot flat plate, the local heat transfer coefficient decreases with distance because (select all that are

avanturin [10]

Answer:

hello the answer options are missing here are the options

A)The thickness of the heated region near the plate is increasing

B)The velocities near the plates are increasing

C)The fluid temperature near the plate are increasing

ANSWER : all of the above

Explanation:

Laminar flow is the flow of a type of fluid across the surface of an object following regular paths and it is unlike a turbulent flow which flows in irregular paths (encountering fluctuations)

For laminar flow over a hot flat plate, the local heat transfer coefficient decreases with distance because :

The thickness of the heated region near the plate is increasing
The velocities near the plates are increasing
The fluid temperature near the plate are increasing

5 0

3 years ago

An automotive Battery is rated at120 A-h. This means that under certain test conditions, it canoutput 1 A at 12 V for 120 hours.

Hitman42 [59]

Answer:

Part A:

In W-h:

Energy Stored=1440 W-h

In Joules:

$Energy Stored=5.184*10^6Joules\\Energy Stored=5.184 MJ$

Part B:

In W-h:

Energy left=240 W-h

In Joules:

Energy left= 8.64*10^5 J

Explanation:

Part A:

We are given rating 120A-h and voltage 12 V

Energy Stored= Rating*Voltage (Gives us units W-h)

Energy Stored=120A-h*12V

Energy Stored=1440 W-h

Converting it into joules (watt=joules/sec)

Energy Stored= $1440 Joules * \frac{3600sec}{h}h$

Energy Stored=5184000 Joules

$Energy Stored=5.184*10^6Joules\\Energy Stored=5.184 MJ$

Part B:

Energy used by lights for 8h=150*8

Energy used by lights for 8h=1200W-h

Energy left= Energy Stored(Calculated above)- Energy used by lights for 8h

Energy left=1440-1200

Energy left=240 W-h

Energy left= $240 Joules * \frac{3600sec}{h}h$

Energy left=864000 Joules

Energy left= 8.64*10^5 J

3 0

4 years ago

Steam at 40 bar and 500o C enters the first-stage turbine with a volumetric flow rate of 90 m3 /min. Steam exits the turbine at

a_sh-v [17]

Answer:

(a) 62460 kg/hr

(b) 17,572.95 kW

Explanation:

Volumetric flow rate, G = 30 m³ / 1 min => 90 / 60 => 1.5

Calculate for h₁ , h₂ , h₃

h₁ is h at P = 40 bar, 500°C => 3445.84 KJ/Kg

Specific volume steam, ц = 0.086441 m³kg⁻¹

h₂ is h at P = 20 bar, 400°C => 3248.23 KJ/Kg

h₃ is h at P = 20 bar, 500°C => 3468.09 KJ/Kg

h₄ is hg at P = 0.6 bar from saturated water table => 2652.85 KJ/Kg

Mass flow rate of the steam, m = G / ц

m = 1.5 / 0.086441

m = 17.35 kg/s

mass per hour is m = 62460 kg/hr

Total Power produced by two stages

= m (h₁ - h₂) + m (h₃ - h₁)

= m [(3445.84 - 3248.23) + (3468.09 - 2652.85)]

= m [ 197.61 + 815.24 ]

= 17.35 [1012.85]

= 17,572.95 kW

Rate of heat transfer to the steam through reheater

= m (h₃ - h₂)

= 17.35 x (3468.09 - 3248.23)

= 17.35 x 219.86

= 3,814.57 kW

8 0

3 years ago

What's the real power if Vrms = 100V, Irms = 2A, and the circuit has a power factor of 0.8?

Temka [501]

Answer:

160 W

Explanation:

The relation is ...

Real Power = (pf)(V)(A)

= 0.8(100)(2) = 160 . . . . watts

7 0

3 years ago