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3 years ago

Why a car making a turn does not have constant velocity

Physics

2 answers:

BabaBlast [244]3 years ago

8 0

A car making a turn is accelerating. Acceleration is defined as a change in speed or direction.

zhenek [66]3 years ago

5 0

Because the car's wheels have treads slowing it down also rubbing against the rode and the theory is every force has a counter force of equal power

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enyata [817]

Answer:

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3 years ago

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The number of organisms that can be sustained by an environment without environmental degradation is__________.

otez555 [7]

Answer:

carrying capacity.

Explanation:

The number of organisms that can be sustained by an environment without environmental degradation is its carrying capacity.

The carrying capacity of a living species in an ecosystem is the species ' maximum population size that the environment could carry indefinitely, given the ecosystem's food, habitat, water, as well as other necessities are sufficient.

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4 years ago

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A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.1 cm/min. At what rate is the volume of

andrew11 [14]

Answer:

$\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Explanation:

Knowing that the volume of a sphere is V=(4/3)πr³ and $\frac{dr}{dt}=-0.1\frac{cm}{min}$

We must find $\frac{dV}{dt}=?$ when r=14cm

V=(4/3)πr³ ⇒

$\frac{dV}{dt}=\frac{4}{3}\pi3r^{2}\frac{dr}{dt}\\\frac{dV}{dt}=4\pi r^{2}(-0.1\frac{cm}{min})$

and r=14cm then

$\frac{dV}{dt}=4\pi(14cm)^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=4\pi196cm^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Note: as you can see the relationship of change of r with respect to t is negative because it is a decrease, and also its volume ratio

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4 years ago

why do a circulatory system is important in meeting the needs of all cells throughout an animals body

valentinak56 [21]

The circulatory system is important in meeting the needs of all cells in the body because it offers means of transport by which cells obtain the materials needed to live and function. The functions of the circulatory system by which the cells are supported include: 1. Respiration- oxygen is delivered to the cells and carbon dioxide is removed from them. 2. Nutrition- nutrients for energy are supplied to every cell in the body. 3. Waste removal- metabolic waste products are taken away before they accumulate and become harmful to the cells. 4. Cellular communication- hormones are transported to the cells and organs that need them for proper functioning. 5.Thermoregulation- As blood circulates, it keeps body temperature balanced and thus cells are able to carry out processes well.

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4 years ago

A 100 kg roller coaster comes over the first hill at 2 m/sec (vo). The height of the first hill (h) is 20 meters. See roller dia

aleksandr82 [10.1K]

For the 100 kg roller coaster that comes over the first hill of height 20 meters at 2 m/s, we have:

1) The total energy for the roller coaster at the initial point is 19820 J

2) The potential energy at point A is 19620 J

3) The kinetic energy at point B is 10010 J

4) The potential energy at point C is zero

5) The kinetic energy at point C is 19820 J

6) The velocity of the roller coaster at point C is 19.91 m/s

1) The total energy for the roller coaster at the initial point can be found as follows:

$E_{t} = KE_{i} + PE_{i}$

Where:

KE: is the kinetic energy = (1/2)mv₀²

m: is the mass of the roller coaster = 100 kg

v₀: is the initial velocity = 2 m/s

PE: is the potential energy = mgh

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 20 m

The total energy is:

$E_{t} = KE_{i} + PE_{i} = \frac{1}{2}mv_{0}^{2} + mgh = \frac{1}{2}*100 kg*(2 m/s)^{2} + 100 kg*9.81 m/s^{2}*20 m = 19820 J$

Hence, the total energy for the roller coaster at the initial point is 19820 J.

2) The potential energy at point A is:

$PE_{A} = mgh_{A} = 100 kg*9.81 m/s^{2}*20 m = 19620 J$

Then, the potential energy at point A is 19620 J.

3) The kinetic energy at point B is the following:

$KE_{A} + PE_{A} = KE_{B} + PE_{B}$

$KE_{B} = KE_{A} + PE_{A} - PE_{B}$

Since

$KE_{A} + PE_{A} = KE_{i} + PE_{i}$

we have:

$KE_{B} = KE_{i} + PE_{i} - PE_{B} = 19820 J - mgh_{B} = 19820 J - 100kg*9.81m/s^{2}*10 m = 10010 J$

Hence, the kinetic energy at point B is 10010 J.

4) The potential energy at point C is zero because h = 0 meters.

$PE_{C} = mgh = 100 kg*9.81 m/s^{2}*0 m = 0 J$

5) The kinetic energy of the roller coaster at point C is:

$KE_{i} + PE_{i} = KE_{C} + PE_{C}$

$KE_{C} = KE_{i} + PE_{i} = 19820 J$

Therefore, the kinetic energy at point C is 19820 J.

6) The velocity of the roller coaster at point C is given by:

$KE_{C} = \frac{1}{2}mv_{C}^{2}$

$v_{C} = \sqrt{\frac{2KE_{C}}{m}} = \sqrt{\frac{2*19820 J}{100 kg}} = 19.91 m/s$

Hence, the velocity of the roller coaster at point C is 19.91 m/s.